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galina1969 [7]
3 years ago
8

Help please read directions

Mathematics
2 answers:
Andrei [34K]3 years ago
8 0
-1 3/4 is the answer
Studentka2010 [4]3 years ago
7 0

Answer: - 1 3/4

Step-by-step explanation: You have to keep the first number and flip the second number, and you end with -1 3/4

PLEASE MARK BRAINLIEST

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For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q


4 0
3 years ago
(60 points)
natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56

5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}

6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}

8 0
3 years ago
What are the center and radius of the circle defined by the equation<br> x2 + y2 - 6x+By+21=0 ?
podryga [215]

    (x-3)2+(y+B2)2+By=-12+B24

5 0
3 years ago
Easy problems I'm having trouble remembering how to do!
beks73 [17]
<h2>Answer:</h2>

1. - 2°C + 4°C

= 2°C.

2. 3/4 × 4

= 3pounds.

7 0
2 years ago
Solve the system by graphing
Marta_Voda [28]

\left\{\begin{array}{ccc}-2x=2y-4\\2x-y=-5\end{array}\right\\\\2y-4=-2x\ \ \ \ |+4\\2y=-2x+4\ \ \ \ |:2\\y=-x+2\\for\ x=0\to y=-0+2=2\to(0,\ 2)\\for\ x=2\to y=-2+2=0\to(2,\ 0)\\\\2x-y=-5\ \ \ \ |-2x\\-y=-2x-5\ \ \ \ |\cdot(-1)\\y=2x+5\\for\ x=0\to y=2(0)+5=5\to(0,\ 5)\\for\ x=-2\to y=2(-2)+5=1\to(-2,\ 1)\\\\Answer:\ (-1,\ 3)\to\ x=-1,\ y=3

7 0
3 years ago
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