Answer:
Explanation:
Given
485 L
Required
Determine the measurement not equal to 485L
<em>From standard unit of conversion;</em>
1 KL = 1000 L
<em>Multiply both sides by 485</em>
<em>Divide both sides by 1000</em>
---- This is equivalent
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<em>From standard unit of conversion;</em>
1000 mL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
Hence; is not equivalent to 485L
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<em>From standard unit of conversion;</em>
100 cL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
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μL
<em>From standard unit of conversion;</em>
1000000 μL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
From the list of given options;
is not equivalent to 485L
Explanation:
The standard entropy change of a reaction has a positive value. This reaction results in an increase in entropy.
Positive entropy means the system has increased its degree of disorderness.
Answer:
The coffee has a higher temperature because a pool is so you can have fun and relax in while coffee can warm you up by drinking it.
Explanation:
Hope it helps :)
Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2
<span>B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) </span>
<span>C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) </span>
<span>D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
</span>Answer is: B.
Chemical reaction: F<span>e</span>₂O₃<span>(s) + 3CO(g) → 2Fe(s) + 3CO</span>₂<span>(g);</span>ΔH = <span>+ 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.</span>