Answer:
D. 40 % increase
Step-by-step explanation:
r = k[A]²/[B]
The rate is inversely proportional to [B]. If [B] is doubled, the rate is halved.
We must double this rate to get back to the original.
The rate is directly proportional to [A]².
2 = [A]₂/[A]₁² Take the square root of each side
√2 = [A]₂/[A]₁ Multiply each side by [A]₁
[A]₂ = √2[A]₁
[A]₂ = 1.41[A]₁
We must increase [A] by 41 %.
Answer:
V₂ = 106.5 mL
Explanation:
Given data:
Initial volume =200 mL
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308 K)
Final temperature = 55°C (55+273 = 328 K)
Final volume = ?
Final pressure = 4 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm ×200 mL × 328 K / 308 K ×4 atm
V₂ = 131200 atm .mL. K / 1232 K.atm
V₂ = 106.5 mL
Answer:
division of atoms are neither created nor destroyed therefore atoms can only be rearranged
The atomic number of Li is 3
Electron configuration of Li : 1s² 2s¹
The atomic number of Na is 11
Electron configuration of Na : 1s²2s²2p⁶3s¹
Thus there is one electron in the valence shell of Li (2s¹) and that of Na (3s¹). However, the valence electron in Na is in a shell that is farther away from the nucleus compared to that of Li. As a result, the Na valence electron will be held less tightly by the nucleus i.e. it will experience a reduced nuclear attraction and can be removed easily than the Li 2s electron.
Answer:
<h2>━☆ﾟ.*･｡ﾟFine, but not as good</h2>
