Answer:
35.453 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A (Cl–35):
Abundance (A%) = 75.77%
Mass of A = 34.969 amu
Isotope B (Cl–37):
Abundance (B%) = 24.23%
Mass of B = 36.966 amu
AVERAGE atomic mass of Cl =?
The average atomic mass of Cl can be obtained as follow:
Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]
Average = 26.496 + 8.957
Average atomic mass of Cl = 35.453 amu.
Answer:
A scientist measures the standard enthalpy change for the following reaction to be -139.5 kj :
h2(g) + c2h4(g)c2h6(g)
based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of c2h4(g) is _____ kj/mol
Explanation:
Hydrogen ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K)
H2 (g)
0
0
130.7
Carbon ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K)
C2H6 (g)
-84.7
-32.8
229.6
Answer:
163.44 g
Explanation:
We know that one ton is equal to 2000 lbs and one lb is equal to 454 grams.
Solution:
1.80 × 10∧-4 ton× 2000 lb/ton× 454 g/lb
1.80 × 10∧-4 ton× 2× 10³lb/ton× 454 g/lb
1634.4 g/ 10 = 163.44 g
Answer:
2Mg^+ +O2 right arrow 2MgO
Explanation:
