Answer:
The answer to the question is;
Based on their acceleration the rank of the satellites from largest to smallest is.
B >→ A >→ E >→ C >→ F >→ D.
Explanation:
Acceleration is given by 
Therefore the acceleration for each of the satellite is given by
Satellite A) 
= 5.12 m/s²
Satellite B) 
= 10.24 m/s²
Satellite C) 
= 2.56 m/s²
Satellite D) 
= 0.16 m/s²
Satellite E) 
= 2.88 m/s²
Satellite F) 
= 0.64 m/s²
Therefore in order of decreasing acceleration, from largest to smallest we have
Satellite B) > Satellite A) >Satellite E) >Satellite C)>Satellite F)>Satellite D).
A 59 kg sprinter, starting from rest, runs 47 m in 7.0 s at constant acceleration.?
What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s?
Instantaneous Power is the force times velocity
P = Fv
Because the acceleration is constant, the force will be constant as well
F = ma
P = mav
for constant acceleration, the velocity at each time is found using
v = at
P = ma(at) = ma²t
find the acceleration using kinematic equation
s = ½at²
a = 2s/t²
a = 2(47) / 7.0²
a = 1.918 m/s²
P(2.0) = 59(1.918²)2.0 = 434.25 W = 0.43 kW
P(4.0) = 59(1.918²)4.0 = 868.51 W = 0.87 kW
P(6.0) = 59(1.918²)6.0 = 1302.76 W = 1.3 kW
I hope this helped.
Answer:
a = 1.41 m/s²
Explanation:
Given that
mass ,m= 41 kg
F₁ = 65 N , θ = 59°
F₂ = 35 N ,θ = 32°
The component of Force F₁
F₁x= F₁cos59° i
F₁x= 65 x cos59° i = 33.47 i
F₁y= - F₁ sin 59° j
F₁y= - 65 x sin 59° j = - 55.71 j
The component of Force F₂
F₂x= F₂ sin 32° i
F₂x= 35 x sin 32° i = 18.54 i
F₂y= F₂ cos 32° j
F₂y= 35 x cos 32° j = 29.68 j
The total force F
F= 33.47 i + 18.54 i - 55.71 j + 29.68 j
F= 52.01 i - 26.03 j
The magnitude of the force F
F=58.16 N
We know that
F= m a
a= Acceleration
m=mass
58.16 = 41 x a
a = 1.41 m/s²
Answer:
Part a)
Part b)
Explanation:
Part a)
Initial value of magnetic flux is given as
so we have
Final flux through the loop is given as
now EMF is given as
Part b)
If magnetic field is constant while Area is changing
So EMF is given as
Answer:
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