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Lera25 [3.4K]
2 years ago
13

Draw a closed circuit diagram of the battery of 2 cells arranged in series, connecting wire, switch and bulb; mark the direction

of the current.
pls ill give brainly
Physics
1 answer:
ch4aika [34]2 years ago
5 0
This is the open switch 2 cells connecting wire and bulb

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You are working in a shoe test laboratory measuring the coefficients of friction for running shoes on a variety of surfaces. The
AnnZ [28]

Answer:

0.75

Explanation:

Since the static frictional force is the maximum force applied just before sliding, our frictional force, F is 300 N.

Since F = μN where μ = coefficient of static friction and N = normal force = 400 N (which is the downward force applied against the surface).

So, μ = F/N

= 300 N/400 N

= 3/4

= 0.75

So, the  coefficient of static friction μ = 0.75

6 0
2 years ago
Select the volume units that are greater than one liter.
Andreas93 [3]
A.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter =  1,000,000 liters


hope this helps
5 0
2 years ago
Read 2 more answers
Instruments in an airplane which is in level flight indicate that the velocity relative to the air (airspeed) is 180.00 km/h and
snow_lady [41]

Answer:

Explanation:

From the given information:

The coordinate axis is situated in the east and north direction.

So, the north will be the  y-axis and the east will be the x-axis

Similarly, the velocity of the plane in regard to the air in the coordinate system will be v_{P/A} = v( cos \theta \ i + sin \theta \ j)

where:

v_{P/A} = velocity of the plane in regard to the air

v = velocity

θ =  angle of inclination of the plane with respect to the horizontal

replacing v = 180 km/ and θ = 20° in above equation, then:

The velocity of the airplane in the coordinate system as:

v_{P} = v_o( cos \phi \ i + sin \phi \ j)

where;

v_p = velocity of the airplane

v_o = velocity

∅ = angle of inclination with regard to the base axis;

Then; replacing  v_o  = 150 km/h and ∅ = 30°

Therefore, the velocity of the plane in the system is :

v_p = v_A + v_{P/A}

v_A=  v_P  -v_{P/A}   --- (1)

v_A= ( 150 cos 30° - 180 cos 20°)i + ( 150 sin 30° - 180sin 20°)j

v_A= (-39.24 km/h)i + (13.44 km/h) j

The magnitude is:

v_A= (-39.24 km/h)i + (13.44 km/h) j

|v_A|^2 = \sqrt{ (-39.24 km/h)^2+ (13.44 km/h)^2}

v_A = 41.48 km/h

The airplane is moving at an angle of the inverse tangent to the abscissa and ordinate.

The angle of motion is:

tan θ = 39.24/13.44

tan θ = 2.9

θ  = tan ^{-1} (2.9)

θ  =  70.97°

The angle of motion is  70.97° from west of north with a velocity of 41.48 km/h.

5 0
3 years ago
Question 2 10
ss7ja [257]
B Ik it all just know who they’ll you
8 0
2 years ago
A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
rusak2 [61]

Answer:

Spring constant in N / m = 6,000

Explanation:

Given:

Length of spring stretches = 5 cm = 0.05 m

Force = 300 N

Find:

Spring constant in N / m

Computation:

Spring constant in N / m = Force/Distance

Spring constant in N / m = 300 / 0.05

Spring constant in N / m = 6,000

8 0
2 years ago
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