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nikitadnepr [17]
2 years ago
12

Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set

for 37 V. What is the smallest resistance you can measure?
Physics
1 answer:
VikaD [51]2 years ago
8 0

To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as

V = IR \rightarrow R = \frac{V}{I}

Our values are

I = 500mA = 0.5A

V = 37V

Replacing,

R = \frac{V}{I}

R = \frac{37}{0.5}

R = 74 \Omega

Therefore the smallest resistance you can measure is 74 \Omega

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1 year ago
PE=30J, m=?, g=10m/s2, h=10m
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Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
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With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

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Do operations that you can with what is given first.

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Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

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