Answer:
100 m
Explanation:
Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t
Speed of Arthur = 3 m/s
Speed of Betty = 2 m/s
Distance = Speed × time
Distance covered by Arthur = 3t
Distance covered by Betty = 2t
The distance covered by both of them will be 100 m

The speed of dog is 5 m/s
Spot is running back and forth at 5 m/s for 20 seconds
In 20 seconds the distance covered by the dog is

Fahrenheit because the boiling point of water is 100 degrees Celsius which is 212 Fahrenheit which is very hot, and that would be about 200 Kelvin so therefore the answer is that the temperature was recorded in Fahrenheit not Kelvin or Celsius
Answer:
(a) 
(b) 
Explanation:
We will take ground level as origin and upward is positive direction
the givens are

Part (a)
To find the final velocity we use the kinematic equation
So

Part (b)
To find time of rock trip until it touches the ground we will use simple kinematic equation or simple motion equation

Notice that we substituted vf with negative sign because its direction is downwards
Answer:
a)0.674 kg b) 2.2 s c) 0.9 m/s²
Explanation:
The amplitude of the ball (xo) = 11.0cm, half way between its equilibrium point its maximum displacement x = 11 cm / 2 = 5.5 cm = 5.5 / 100 in meters = 0.055 meters, speed at this point = 27.2 cm /s = (27.2 / 100) in m/s = 0.272 m/s,
spring constant K = 5.5 N/m
a) The mass of the ball (m) can be calculated using the formula below
v =√ (x²o - x²)K/m
make m subject of the formula
v² = (xo² - x²) K/m
m = K ( xo² - x²) / v²
m = 0.674kg
b) The period of the oscillation can be calculated by the following formula
T = 2π√ (m /K)
substitute the values into the formula
T = 2 × 3.142 × √ (0.674/ 5.5) = 2.2s
c) The maximum acceleration of the ball which occurs at the maximum displacement of the ball can be calculated by the following formula
a = K / m × x ( maximum displacement of the body) = 5.5 / 0.674 × 0.11 = 0.9 m/s²
The ardor determines the result of a reaction.
[formula A]+[formula B]—> [formula C]
Here, the arrow signifies that when adding formula A and B, you get formula C. An arrow can also go both directions.
[formulaA]+[form.B]<—>[formulaC]+[form.D]
Here, the double sided arrows means that adding formulas A and B will give you C and D, and adding formulas C and D will give you A and B.