Answer:
The right solution is "24.39 per sec".
Explanation:
According to the question,
⇒
The time will be:
⇒
hence,
⇒
Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set
1 answer:
To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as
Our values are
Replacing,
Therefore the smallest resistance you can measure is
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Answer: wavelength is
The frequency of the microwave is, f = 2.30 GHz.
To Find frequency use the formula:
λ
Where, c is the speed of electromagnetic wave or light. f is the frequency, and λ is the wavelength of light.
Rearranging,
Plug in the values,
Answer:
1.
2.
3.The results from part 1 and 2 agree when r = R.
Explanation:
The volume charge density is given as
We will investigate this question in two parts. First r < R, then r > R. We will show that at r = R, the solutions to both parts are equal to each other.
1. Since the cylinder is very long, Gauss’ Law can be applied.
The enclosed charge can be found by integrating the volume charge density over the inner cylinder enclosed by the imaginary Gaussian surface with radius ‘r’. The integration of E-field in the left-hand side of the Gauss’ Law is not needed, since E is constant at the chosen imaginary Gaussian surface, and the area integral is
where ‘h’ is the length of the imaginary Gaussian surface.
2. For r> R, the total charge of the enclosed cylinder is equal to the total charge of the cylinder. So,
3. At the boundary where r = R:
As can be seen from above, two E-field values are equal as predicted.