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3 years ago

Restaurant L made 6 dumplings more than Restaurant M.

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Answer:

I am not completely sure with this

Step-by-step explanation:

L restaurant=6 + M

N Restaurant= 2 x L+M

Total dumplings= 72= (6+M) + M + 2x L+M

Dumplings in N restaurant=

suppose m=2

so L= 6+M=8

so L and M will be 10=8+2

N=10 x 2= 20

so u should try and find out like that

Im in elementary school so im not sure

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-4 -2 0 2 4 form the set of even integers true or false

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Answer:

True

Step-by-step explanation:

An integer is anything that's not a fraction/decimal, and being even is common knowledge

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3 years ago

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What should be subtracted from -8xy + 2x^2 + 3y^2 to get x^2 + 2

Minchanka [31]

Answer:

x^2 - 8xy + 3y^2 - 2

Step-by-step explanation:

(-8xy + 2x^2 + 3y^2) - unknown = x^2 + 2

- unknown = x^2 + 2 + 8xy - 2x^2 - 3y^2

- unknown = -x^2 + 8xy - 3y^2 + 2

Unknown = x^2 - 8xy + 3y^2 - 2

Check:

(-8xy + 2x^2 + 3y^2) - (x^2 - 8xy + 3y^2 - 2)

= -8xy + 2x^2 + 3y^2 - x^2 + 8xy - 3y^2 + 2

= -8xy + 8xy + 2x^2 - x^2 + 3y^2 - 3y^2 + 2

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8 0

3 years ago

There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s

harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

Original Mean = $70,000

$\frac{\sum X}{n}$ = $70,000 ⇒ $\sum X$ = 70,000 * 10 = $700,000

New $\sum X$ after change = $700,000 - $100,000 + $1,000,000 = $1600000

Therefore, New mean = $\frac{1600000}{10}$ = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = $20000^{2}$ i.e. $20000^{2}$ = $\frac{\sum x^{2} - n*xbar }{n -1}$

Original $\sum x^{2}$ = ( $20000^{2}$ * (10-1)) + (10 * 70,000) = $3,600,700,000

New $\sum x^{2}$ = $3,600,700,000 - $100,000^{2} + 1,000,000^{2}$ = 9.936007 * $10^{11}$

New Variance = $\frac{new\sum x^{2} - n*new xbar }{n -1}$ = $\frac{9.936007 *10^{11} - 10*160000 }{10 -1}$ = 1.103999 * $10^{11}$ Therefore, standard deviation after change = $\sqrt{1.103999 * 10^{11} }$ = $332264.804 .