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lilavasa [31]
3 years ago
10

This equation shows how the total cost of visiting the art museum as a member is related to the number of visits. C = 9.2v + 21.

2 The variable v represents the number of visits to the art museum, and the variable c represents the total cost of those visits. What is the maximum number of visits a member of the art museum can make for a total cost of $76.40?
Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

6

Step-by-step explanation:

C=9.2v + 21.2

76.4 = 9.2v + 21.2

76.4 - 21.2 = 9.2v

55.2 = 9.2v

v= 55.2 / 9.2 = 6

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Answer:

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Step-by-step explanation:

At first we use "BODMAS" rule.

Given,

(3.5×10^13)-(1.4×10^12)/3×10^9

So, we will break the brackets at first. With the help of excel, we can get the desired result. The following images will show you the step-by-step result.

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Which is the degree measure of an angle whose tangent is 5.67?
kolbaska11 [484]

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Step-by-step explanation:

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3 years ago
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
Marina86 [1]

Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

Since a is a multiple of 9, then a has the form a=9s for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form 12=c*b, for c an integer. Then b has the form b=\frac{12}{m}

Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
3 years ago
When a figure is translated, reflected, or rotated, what's the same about the original igure and its image? What's different?
Liula [17]

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The image of a translation, reflection, or rotation is congruent to the original figure, and the image of a dilation is similar to the original figure. Two figures are similar when one can be obtained from the other by a sequence of translations, reflections, rotations, and dilations.

7 0
3 years ago
joe and Eric have to ship 75 packages. Joe can do the job alone in 5 hours. if Eric helps, they get it done in 4 hours. How long
Umnica [9.8K]

Eric took 20 hours to do the job alone.

<u>Step-by-step explanation</u>:

<u>Given </u>:

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The amount of work Joe alone can do per hour = 75/5 = 15 packages.

The amount of work Joe and Eric together do per hour = 75/4 = 18.75

The amount of work Eric alone can do per hour = 18.75 - 15 = 3.75

The time Eric took to complete the entire work = 75 / 3.75 = 20 hours.

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