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lilavasa [31]
3 years ago
10

This equation shows how the total cost of visiting the art museum as a member is related to the number of visits. C = 9.2v + 21.

2 The variable v represents the number of visits to the art museum, and the variable c represents the total cost of those visits. What is the maximum number of visits a member of the art museum can make for a total cost of $76.40?
Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

6

Step-by-step explanation:

C=9.2v + 21.2

76.4 = 9.2v + 21.2

76.4 - 21.2 = 9.2v

55.2 = 9.2v

v= 55.2 / 9.2 = 6

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In the figure, angle A measures 41° and angle D measures 32°. What is the measurement of angle E?
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6 0
3 years ago
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Angle 4=x+30 and angle 2=2x+15. Find the measure of angle 4
kvasek [131]

9514 1404 393

Answer:

  ∠4 = 45°

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6 0
3 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
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