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uysha [10]
4 years ago
15

How many moles are equal to 47.2 g of K2O

Chemistry
2 answers:
HACTEHA [7]4 years ago
7 0

Answer: 0.50 mole K2O

Explanation: To convert the mass of K2O to moles we will need to find the molar mass of K2O.

47.2 g K2O x 1 mole K2O / 94 g K2O

= 0.50 mole K2O

makkiz [27]4 years ago
3 0

Answer:

0.5mole

Explanation:

First, we need to calculate the molar mass of K2O. This is illustrated below:

Molar Mass of K2O = (39x2) + 16 = 78 + 16 = 94g/mol

Mass of the K2O from the question = 47.2g

Number of mole of K2O =?

Number of mole = Mass /Molar Mass

Number of mole of K2O = 47.2/94 = 0.5mole

Therefore, 0.5mole is equal to 47.2g of K2O.

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nignag [31]

Answer:

8.38×10raise to power 23

Explanation:

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no. of miles= given mass/ molar mass

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1 mole of sugar =C12 H22 O11

contains

12× 6.023 × 10 ∆23=72.28× 10∆ 23 ×6.023×10²³

= 8.38× 10²³

4 0
3 years ago
. One mole of N2O4 contains ___________.
ivanzaharov [21]
One molecule of N2O4 contains

two nitrogen
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A sulfur containing amino acid is
SVETLANKA909090 [29]
Cysteine and methionine contain sulfur.
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At a wastewater treatment plant, FeCl3(s) is added to remove excess phosphate from the effluent. Assume the following reactions
RoseWind [281]

Answer : The concentration of Fe^{3+} needed is, 2.37\times 10^4M

Explanation :

First we have to calculate the mole of phosphate.

As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

\text{Moles of phosphate}=\frac{\text{Mass of phosphate}}{\text{Molar mass of phosphate}}

Molar mass of phosphate = 94.97 g/mole

\text{Moles of phosphate}=\frac{1mg}{94.97g/mol}=\frac{0.001g}{94.97g/mol}=1.053\times 10^{-5}mol

Now we have to calculate the concentration of phosphate.

\text{Concentration of phosphate}=\frac{\text{Moles of phosphate}}{\text{Volume of solution}}

\text{Concentration of phosphate}=\frac{1.053\times 10^{-5}mol}{1L}=1.053\times 10^{-5}mol/L

Now we have to calculate the concentration of Fe^{3+}.

The second equilibrium reaction is,

FePO_4\rightleftharpoons Fe^{3+}+PO_4^{3-}

The solubility constant expression for this reaction is:

K_{sp}=[Fe^{3+}][PO_4^{3-}]

Given: K_{sp}=\frac{1}{4}

\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L

[Fe^{3+}]=2.37\times 10^4M

Thus, the concentration of Fe^{3+} needed is, 2.37\times 10^4M

8 0
4 years ago
How many molecules are in 165 g of carbon dioxide?
Svet_ta [14]
М(СО₂)=165 г

н(СО₂)=м(углекислого газа)/М(СО₂)

Н=Nₐ*м(углекислого газа)/М(СО₂)

Н=6.022*1023 * 165/44.01=2.258*10²⁴
6 0
3 years ago
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