Answer:
8.38×10raise to power 23
Explanation:
mass of sugar=density ×volume
=. 1.59g/ml×25ml=39.75
no. of miles= given mass/ molar mass
= 39.75/342.3g / mole
1 mole of sugar =C12 H22 O11
contains
12× 6.023 × 10 ∆23=72.28× 10∆ 23 ×6.023×10²³
= 8.38× 10²³
One molecule of N2O4 contains
two nitrogen
four oxygen
Cysteine and methionine contain sulfur.
Answer : The concentration of
needed is, 
Explanation :
First we have to calculate the mole of phosphate.
As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

Molar mass of phosphate = 94.97 g/mole

Now we have to calculate the concentration of phosphate.


Now we have to calculate the concentration of
.
The second equilibrium reaction is,

The solubility constant expression for this reaction is:
![K_{sp}=[Fe^{3+}][PO_4^{3-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BFe%5E%7B3%2B%7D%5D%5BPO_4%5E%7B3-%7D%5D)
Given: 
![\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%3D%5BFe%5E%7B3%2B%7D%5D%5Ctimes%201.053%5Ctimes%2010%5E%7B-5%7Dmol%2FL)
![[Fe^{3+}]=2.37\times 10^4M](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%3D2.37%5Ctimes%2010%5E4M)
Thus, the concentration of
needed is, 
М(СО₂)=165 г
н(СО₂)=м(углекислого газа)/М(СО₂)
Н=Nₐ*м(углекислого газа)/М(СО₂)
Н=6.022*1023 * 165/44.01=2.258*10²⁴