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Studentka2010 [4]
4 years ago
13

Enter the simplified version of the expressionbelow.(4.7x - 3.25) + (-5.5 - 1.25x)​

Chemistry
1 answer:
Amiraneli [1.4K]4 years ago
4 0
3.45x-8.75 is the simplified version:)
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WILL MARK BRAINLIEST!!!! HELPPPP
Lina20 [59]

Answer:

A single distillation cycle is enough to separate the mixture. ... Simple distillation is the method used to separate substances in mixtures with significantly different boiling points, while fractional distillation is used for mixtures containing chemicals with boiling points close to each other.

Explanation:

5 0
4 years ago
SHOW ALL WORK FOR BRAINLIEST
Anna71 [15]

Answer:

The answer to your question is 37.5 l of water vapor

Explanation:

Data

volume of ethane = 12.5 l

volume of water vapor = ?

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒   4CO₂  +  6H₂O

-Convert the volume of C₂H₂ to moles

                    1 mol of C₂H₂ --------------- 22.4 l

                    x                     --------------- 12.5 l

                             x = (12.5 x 1) / 22.4

                             x = 0.56 moles

-Calculate the moles of water vapor

                 2 moles of C₂H₂ --------------- 6 moles of H₂O

                 0.56 moles of C₂H₂ ----------  x

                          x = (0.56 x 6) / 2

                          x = 1.67 moles of H₂O

-Calculate the volume of water vapor

                          22.4 l of H₂O ----------------- 1 mol

                             x                  ----------------- 1.67 moles

                             x = (1.67 x 22.4) / 1

                             x = 37.5 l

6 0
3 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
Can someone answer this for me
Olenka [21]

Answer:

  1. B
  2. C
  3. E
  4. D
  5. A
  6. B
  7. A
  8. E
  9. C
  10. E
  11. B
  12. D
  13. D
  14. D
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6 0
3 years ago
What is the chemical composition of aragonite?
Alexandra [31]
Calcium carbonate CaCO3<span>


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4 0
3 years ago
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