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3 years ago

. One mole of N2O4 contains ___________.

Chemistry

1 answer:

ivanzaharov [21]3 years ago

7 0

One molecule of N2O4 contains

two nitrogen
four oxygen

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The heat of vaporization for water is 40. 7 kJ/mol. How much heat energy must 150. 0 g of water absorb to boil away completely?

netineya [11]

The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.

The heat of vaporization has been the amount of heat required to vaporize 1 gram of liquid.

The heat required for the vaporization has been given as:

$Q=m\Delta H_{vap}$

<h3 /><h3>Computation for the Heat of vaporization</h3>

The heat of vaporization of water has been given as, $\Delta H_{vap}=40.7\;\rm kJ/mol$

The mass of water sample has been, $m=150\;\rm g$

Substituting the values for the heat energy absorbed, <em>Q:</em>

<em />

<em /> $Q=150\;\times\;40.7\;\rm kJ\\
\textit Q=6,105\;kJ$

The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.

Learn more about heat of vaporization, here:

brainly.com/question/2427061

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3 years ago

GIVING BRAINLIEST HURRY

PIT_PIT [208]

Answer: A
Explanation it gets all mushy THATS a physical change

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3 years ago

Read 2 more answers

A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from

ratelena [41]

Answer: Approximately $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$

===================================================

Work Shown:

We have the following variables

Q = 714 joules = heat required
m = 52 grams = mass
c = specific heat = unknown
$\Delta t$ = 82-30.5 = 51.5 = change in temperature

note: the symbol $\Delta$ is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

$Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\$

The specific heat of the unknown metal is roughly $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$

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3 years ago

Using the equation MgCl2 -> Mg + Cl2, if 5.00 grams of MgCl2 is given, how many grams of Mg is produced?

motikmotik

Answer:

MgCl2-> Mg+Cl

mass 5.00g Mass=1.263g

RFM Mg=24+35.5 ×2= 95 RFM= 24

moles= 5.00÷ 95= 0.0526 Moles=0.0526

Explanation:

mas of Mg= 1.263 grams

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4 years ago

What is an orbital shell

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