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ehidna [41]
3 years ago
10

Help needed please!!!!!!!!

Mathematics
1 answer:
Sonja [21]3 years ago
5 0
Funimobgdhdhehhdhshhdhjsbfhshhwhdhs
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Compute F(s), the Laplace transform of f(t) = e^(5t) (t^2 +4t +7)
MakcuM [25]

Recall that

\mathcal L_s\{t^ne^{ct}\}=\dfrac{n!}{(s-c)^{n+1}}

Then

F(s)=\dfrac2{(s-5)^3}+\dfrac4{(s-5)^2}+\dfrac7{s-5}

3 0
3 years ago
Please help very urgent
Arturiano [62]

Answer:

<em>Marika's calculation is correct</em>

Step-by-step explanation:

<em>Lori has erroneously identified a common ratio of the geometion sequence</em>

<em>one has to divide subsequent term by the preceding term as was correctly by Marika. so Marika's calculation is correct.</em>

<em>hope it helps...</em>

<em>have a great day !!!</em>

8 0
3 years ago
: Find the slope between the two points given. Then, use the slope and point ONE to write the equation of the line in Point-Slop
Ierofanga [76]

Answer:

           slope:      \bold{m=3}

      equation:     \bold{y-2=3(x-1)}

Step-by-step explanation:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(1,\,2)\ \implies\ x_1=1\,,\ y_1=2\\(0,\,-1)\ \implies\ x_2=0\,,\ y_2=-1\\\\m=\dfrac{-1-2}{0-1}=\dfrac{-3}{-1}=3

y-y_1=m(x-x_1)      - point-slope form of Equation of the Line

x_1=1\,,\ y_1=2\,,\ m=3\\\\equation:\\{}\qquad\qquad y-2=3(x-1)

8 0
3 years ago
Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad
Zigmanuir [339]

Answer:

\theta = 5.83\ rad

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

\omega_f^2 = \omega_i^2 + 2 \alpha \theta

0 = \omega_i^2 - 2\times 0.5\times 6.1

\omega_i = \sqrt{6.1}

\omega_i = 2.47\ rad/s

now, angular position calculation at t=3.9 s

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2

\theta = 5.83\ rad

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0
4 years ago
Find the gcf of each pair of monomials <br> 6x2 and 5x2
aleksandrvk [35]

Answer:

its 2  

Step-by-step explanation:

so 6x2 is 12 and 5x2 is 10

u have to find the gcf of 12 and 10 which is 2 :)

8 0
3 years ago
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