Answer:
The molecular formula for the compound is Ag₂C₂O₄, silver oxalate.
Explanation:
This is an easy excersise, we relate the moles of the elements in the compound with the molar mass of the total compound.
The sample weighs 1.372 g, with 0.288 g of O, 0.974 g of Ag and the rest, C
Therefore, 1.372g - 0.288 g - 0.974g = 0.112 g are C
We convert the mass to moles
0.288 g / 16g/mol = 0.018 moles of O
0.974 g / 107.87 g/mol = 0.00903 moles of Ag
0.112 g / 12 g/mol = 0.00933 moles of C
Now, the use of the molar mass of the compound. Let's prepare some rules of three:
1.372 g of compound contain 0.018 moles of O, 0.00903 moles of Ag and 0.00933 moles of C
Then, 308.8 g of compound (a mol) must contain:
(308.8 . 0.018) / 1.372 = 4 moles of O
(308.8 . 0.00903) / 1.372 = 2 moles of Ag
(308.8 . 0.00933) / 1.372 = 2 moles of C
The molecular formula for the compound is Ag₂C₂O₄, silver oxalate.
