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Oksi-84 [34.3K]
3 years ago
7

A gas that has a volume of 28 liters, a temperature of 45 0 C, and an unknown pressure has its volume increased to 34 liters and

its temperature decreased to 35 0 C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?
Chemistry
1 answer:
pickupchik [31]3 years ago
7 0

Answer:

2.15 atm

Explanation:

P1=P2V2T1/V1T2

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Fossil age can determine organism changes related to the time scale. Please select the best answer from the choices provided T F
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Answer:

True

Explanation:

Fossil age can determine organism changes related to the time scale. Fossils provide scientists with evidence that allows them to hypothesize how living organisms have evolved over time.

fossil can be studied to determine what kind of organism it represents, how the organism lived, and how it was preserved. However, by itself a fossil has little meaning unless it is placed within some context. The age of the fossil must be determined so it can be compared to other fossil species from the same time period. Understanding the ages of related fossil species helps scientists piece together the evolutionary history of a group of organisms.

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It is necessary to use models to study sub- microscopic objects such as atoms and molecules because they are too small to be seen.

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The equation for the reaction between copper and nitric acid is vCu + wHNO3--->xCu(NO3)2 + yNO + zH2O Balance the equation an
lana [24]

Answer:

The coefficients of the balanced equation are:

  • v= 1
  • w= 4
  • x= 1
  • y= 2
  • z=2

Explanation:

The Law of Conservation of Matter, also called the Law of Conservation of Mass or the Lomonósov-Lavoisier Law, postulates that "mass is neither created nor destroyed, it is only transformed". This means that the reagents interact with each other and form new products with different physical and chemical properties than the reagents, but the amount of matter or mass before and after a transformation (chemical reaction) is always the same. In other words, then the mass before the chemical reaction is equal to the mass after the reaction.

Then, you must balance the following chemical equation:

v Cu + w HNO₃ → x Cu(NO₃)₂ + y NO + z H₂O

For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

  • Left side:   1 copper, 1 hydrogen, 1 nitrogen and 3 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Generally, hydrogen and oxygen balance in the end. So you balance nitrogen first, because copper is already balanced (there is the same amount on both sides of the reaction). If w = 2, then:

  • Left side:   1 copper, 2 hydrogen, 2 nitrogen and 6 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

But you see then that the oxygen is unbalanced and you have less quantity in the reagents. Then w must be greater. Being w = 4:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

Going back to the idea of ​​balancing nitrogen, being y = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 4 nitrogen and 9 oxygen.

Balancing the hydrogen, being z = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.

Since you have the same amount of each element on each side of the reaction, the reaction is balanced. Then, the balanced equation is:

Cu + 4 HNO₃ → Cu(NO₃)₂ +  2 NO + 2 H₂O

Finally:

  • <u><em>v= 1</em></u>
  • <u><em>w= 4</em></u>
  • <u><em>x= 1</em></u>
  • <u><em>y= 2</em></u>
  • <u><em>z=2</em></u>
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