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2 years ago

Fluorine + sodium chloride → sodium fluoride + __________. What is the missing chemical name?

Chemistry

1 answer:

Deffense [45]2 years ago

7 0

Answer:

Chlorine (Cl)

Explanation:

The equation would be:

$F+NaCl$ → $NaF + Cl$

This is because no atom is lost in a reaction. Chlorine would be the missing chemical as it is on the other side of the equation and needs to be accounted for on the products side.

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After mixing the solutions in a separatory funnel, the stopper should be ________and the liquid should be ________and the layers

sdas [7]

Answer:

The answer is below

Explanation:

The separation technique is used for separating immiscible liquids.

When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.

The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.

When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.

After completely draining the first layer, the second layer should be collected in a new flask.

After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.

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3 years ago

What is the mass % of iron in Fe(CH3CO2)2<br><br> (Fe=iron=55.85)

Serjik [45]

The mass percentage is 15.1465%.

5 0

3 years ago

HEMP ME ITS DUE BY MIDNIGHT

balu736 [363]

Answer:

Explanation:

Option B is the correct answer

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2 years ago

Read 2 more answers

Give the result of the following mathematical operations to the correct number of significant figures. 5.659 * (3.496 - 2.814) =

shtirl [24]

Answer:

The result is 3.859 in which we use four significant figures.

Explanation:

We start by solving the mathematical operation :

$5.659.(3.496-2.814)=5.659(0.682)=3.859438$

The result for the operation is 3.859438 but the numbers in the operation are given with four significant figures and that is why we are going to use four significant figures to express the result

To express 3.859438 with four significant figures we use the first four digits that appear from left to right starting by the first digit that is different to zero

In this case : 3.859 will be the result with four significant figures.

We also use a rule that says : To decide if the last significant figure remains the same we look for the value of the digit at its right.

If that number is greater than or equal to 5 ⇒ we sum one to the last significant figure

For example 3.859738 = 3.860 with four significant figures because the ''7'' is greater that 5

If that number is less than 5 ⇒ the last significant figure remains the same

In our case : 3.859438 = 3.859 because ''4'' is less than ''5''

7 0

3 years ago

Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um

Andre45 [30]

Answer:

$\large \boxed{\text{0.0038 mol/L}}$

Explanation:

1. Calculate the initial moles of acid and base

$\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}$

2. Calculate the moles remaining after the reaction

OH⁻ + H₃O⁺ ⟶ 2H₂O

I/mol: 0.0053 0.005 00

C/mol: -0.00500 -0.005 00

E/mol: 0.0003 0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

$\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}$

8 0

3 years ago