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melomori [17]
2 years ago
6

Calculate the percent mass of a solution of 5 g NaOH in 95 g of H2O. ​

Chemistry
1 answer:
eduard2 years ago
7 0

Answer:

=50g NaOH) then,no.of moles of the NaOH solution=50g/40g=1.25 moles/litre

Explanation:

answer=50g NaOH

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icang [17]

Answer: Option (d) is the correct answer.

Explanation:

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5 0
3 years ago
How many moles of sodium hydroxide would react with 1 Mole of sulphuric acid?
Paul [167]

Answer:

Two moles.

Explanation:

Sulphuric (sulfuric) acid \rm H_2SO_4 is a diprotic acid. When one mole of \rm H_2SO_4 molecules dissolve in water, two moles of \rm H^{+} ions would be produced.

\rm H_2SO_4 \to 2\, H^{+} + {SO_4}^{2-}.

On the other hand, sodium hydroxide \rm NaOH is a monoprotic base. When one mole of \rm NaOH formula units dissolve in water, only one mole of hydroxide ions \rm OH^{-} would be produced.

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