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melomori [17]
2 years ago
6

Calculate the percent mass of a solution of 5 g NaOH in 95 g of H2O. ​

Chemistry
1 answer:
eduard2 years ago
7 0

Answer:

=50g NaOH) then,no.of moles of the NaOH solution=50g/40g=1.25 moles/litre

Explanation:

answer=50g NaOH

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Answer:

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Explanation:

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How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

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PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

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R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

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The formula for number of moles =

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Step 2

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Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

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