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nekit [7.7K]
2 years ago
14

What is the mass of 1.72 moles of BaSO4?

Chemistry
1 answer:
yarga [219]2 years ago
4 0

Explanation:

mass = Moles * molar mass

molar mass of BaSO4 = 112+32+64= 208

= 1.72*208 = 357.76

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You and your friend live in different states and plant identical hydrangea bulbs in your garden. When they bloom, you send each
vladimir1956 [14]

Answer:

The acid in the soil

Explanation:

The more acid the bluer in terms of hydrangea flowers if there was a balance between the two it will be half and half of the two colors.

3 0
3 years ago
Read 2 more answers
How many molecules are in the quantities below.? 2.0 moles
matrenka [14]
Mole=number of molecules/6.02x10²³
mole=2
number of molecules= 2x6.02x10²³
number of molecules=12.04x10²³
5 0
3 years ago
If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

8 0
3 years ago
PLEASE HELP ASAP
Dahasolnce [82]

Answer:0,25 g/cm3 creo

Explanation:densidad es masa entre volumen

5 0
3 years ago
Read 2 more answers
What is the theoretical yield of NaBr
dolphi86 [110]

The theoretical yield of NaBr given that 2.36 moles of FeBr₃ reacts is 7.08 moles

<h3>Balanced equation </h3>

2FeBr₃ + 3Na₂S → Fе₂S₃ + 6NaBr

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

<h3>How to determine the theoretical yield of NaBr</h3>

From the balanced equation above,

2 moles FeBr₃ reacted to produce 6 moles of NaBr

Therefore,

2.36 moles FeBr₃ will react to produce = (2.36 × 6) / 2 = 7.08 moles of NaBr

Therefore,

Thus, the theoretical yield of NaBr is 7.08 moles

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

7 0
2 years ago
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