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Sholpan [36]
3 years ago
12

A chemical formula represents:

Chemistry
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

no

Explanation:

it is a molecular formula that represents the number atoms and type of atoms

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How many grams of Ca(OH)2are required to make 1.5 L of a 0.81 M solution?
FrozenT [24]

Answer:

Mass = 90.28 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Volume of solution= 1.5 L

Molarity of solution = 0.81 M

Solution:

First of all we will calculate number of moles.

Molarity = number of moles / volume in L

by putting values,

0.81 M = Number of moles / 1.5 L

Number of moles = 0.81 M × 1.5 L

Number of moles = 1.22 mol

Mass of Ca(OH)₂ in gram:

Mass = number of moles × molar mass

Mass = 1.22 mol × 74.09 g/mol

Mass = 90.28 g

5 0
3 years ago
Nucleic acids are chains of 5-carbon sugars linked by ____ bonds with an organic base protruding from each sugar.
Mekhanik [1.2K]
<span>B) phosphodiester </span> is the correct answer
3 0
4 years ago
What is the frequency of a radio wave with a wavelength of 578.0m
Radda [10]

Answer:

0.0017 Hz

Explanation:

the solution is in the photo

4 0
3 years ago
C10H22 &gt; C8H18+C2H4 if only ethane can be sold what is the atom econmy of this process
insens350 [35]

Answer:

The atom economy of ethane in this process is 19.72 %.

What is atom economy?

The conversion efficiency of a chemical reaction in terms of all the atoms involved and the desired products produced is known as atom economy (atom efficiency/percentage).

Explanation:

C₁₀H₂₂ → C₈H₁₈ + C₂H₄

Molecular weight of C₁₀H₂₂ = 142.28

Molecular weight of C₈H₁₈ = 114.228
Molecular weight of C₂H₄ = 28.053

% Atom economy =     \frac {Molecular weight of C2H4} {Molecular weight of C10H22}

                             = \frac{28.053}{142.28}*100

                             = 19.716 %

                             ≈ 19.72 %


To know more about atom economy, click on the link

brainly.com/question/17159753

#SPJ9

5 0
1 year ago
The most important commercial ore of chromium is chromite (FeCr2O4). One of the steps in the process used to extract chromium fr
Mars2501 [29]

Answer:

1 mole FeCr2/ 1 mole FeCr2O4

Explanation:

We have to write down the equation of the reaction before we can answer the question;

2C(s) + FeCr2O4(s) -------> FeCr2(s) + 2CO2(g)

By inspection of this reaction equation, we can clearly see that the mole ratio of the reactants and products is 2:1:1:2.

Specifically, the ratio of chromites to ferrochrome is 1:1

Hence;

The mole ration required to convert chromites to ferrochrome is;

1 mole FeCr2/ 1 mole FeCr2O4

4 0
3 years ago
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