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Ber [7]
3 years ago
5

Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charg

e a 50 ampere-minute 12 volt battery with 600j of energy stored in it
Physics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

12.245m3

Explanation:

The electric energy is created by The potential energy substended by the specific volume of water in dam.

Electric energy is calculated as

E= Q× V

E is Energy, Q is charge and V is Voltage

Note that this energy has been given and is 60Joules

From conservation of energy it means;

M× g×h = 60

Where M is the mass of water.

g is acceleration of free fall due to gravity which is 9.8m/S2

h is the height of water flow.

From change of subject of formula for M; we have:

M = 60/ g × h

= 60/ 9.8 × 0.5

= 12.245kg

Now how much water required means the volume of water;

Note density = mass/volume

Therefore volume = mass/density

=12.245/1= 12.245m3

Note the density of water is 1kg/m3

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Answer:

a)

two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign. both charges are positive(+) or Negative (-)

b)

both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

Explanation:

Given that;

L = 0.26 m

k = 180 N/m

x = 0.039 m

a)

we know that two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign.

b)

Spring force F = kx

F = 180 × 0.039

F = 7.02 N

Now, Electrostatic force F = Keq²/r²

where r = L + x = ( 0.26 + 0.039 )

we know that proportionality constant in electrostatics equations Ke = 9×10⁹ kg⋅m3⋅s−2⋅C−2

so from the equation; F = Keq²/r²

Fr² = Keq²

q = √ ( Fr² / Ke )

we substitute

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q =  √ (0.627595 / 9×10⁹)

q = √(6.97 × 10⁻¹¹)

q = 8.35 × 10⁻⁶ C

Therefore both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

5 0
3 years ago
Which is more dense lead or Gold ?
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Gold is more dense.

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How much energy (in kilojoules) is required to convert 200 mL of diethyl ether at its boiling point from liquid to vapor if its
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55.96kJ

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Energy = mass of diethyl ether × enthalpy of vaporization of diethyl ether

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Mass = d × v = 0.7138 × 200 = 142.76g

Enthalpy of vaporization of diethyl ether = 29kJ/mol

MW of diethyl ether (C2H5)2O = 74g/mol

Enthalpy in kJ/g = 29kJ/mol ÷ 74g/mol = 0.392kJ/g

Energy = 142.76g × 0.392kJ/g = 55.96kJ

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A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
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Answer:

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Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

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