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Rom4ik [11]
3 years ago
9

A gas can compress and change shape easily. How do these properties relate to the motion of atoms in a gas?

Physics
1 answer:
Ksju [112]3 years ago
3 0

Answer:

The atoms in a gas move about freely and have a lot of space between them.

Explanation:

Just took the test on edge 2020

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A 2.5-cm-diameter parallel-plate capacitor has a 2.2 mm spacing. The electric field strength inside the capacitor is 6.0×104 V/m
vladimir2022 [97]

Explanation:

The given data is as follows.

     Separation between two plates, d = 2.2 mm = 2.2 \times 10^{-3} m

     Electric field strength inside the capacitor, E = 6.0 \times 10^{4} V/m

Therefore, we will calculate the potential difference across the capacitor as follows.

              V = Ed

                  = 6.0 \times 10^{4} V/m \times 2.2 \times 10^{-3} m

                  = 1.32 V

Thus, we can conclude that the potential difference across the given capacitor is 1.32 V.

3 0
3 years ago
A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w
Grace [21]

Answer:

4.3 * 10 N

Explanation:

To calculate torque, we multiply the distance from the pivot by the perpendicular (the part of the force that acts at right angles to the displacement vector) component of the force to the displacement vector from the pivot.

torque  = distance from pivot *  perpendicular force

170 Nm= 0.4 m * F

F = 425 N = 4.3 * 10 N rounded off to two significant figures

4 0
3 years ago
You are preparing breakfast and slide a plate on the countertop. If the countertop. If the countertop is 1.05 m above the floor
NISA [10]
1- .46s
2. -0.34m



Hope this helps!
5 0
2 years ago
A hydraulic system for a dentist's chair is designed to be able to lift 3,112 newtons. The surface area over which this force is
In-s [12.5K]

Answer:

13.8 N

Explanation:

Pressure on the one end of the hydraulic system = Pressure on the other end

Pressure = Force / Area where Force is in Newton, area is in m²

so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end

3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²

cross multiply

44016.97 × 0.000314 = 13.82 N

5 0
3 years ago
A block moves up a 30 degree incline under the action of three applied forces. F1 is horizontal and of magnitude 40 N. F2 is nor
Alja [10]

Answer

given,

F₁ is horizontal = 40 N

F₂ is normal = 20 N

F₃ is parallel = 30 N

work done by

W₂ = 0 as force is acting perpendicular to the direction of motion.

as the motion moved to 0.8 cm

W₃ = F₃ x d

W₃ = 30 x 0.8

W₃ = 24 J

W₁ = F₁ x d

W₁ = F₁ cos ∅ x d

W₁ = 40 cos 30⁰ x 0.8

W₁ = 27.21 J

4 0
3 years ago
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