Answer:
The answer to your question is C = 1.116 J/g°C
Explanation:
Data
Q = 400 J
mass = 5.6 g
Temperature 1 = T1 = 23°C
Temperature 2 = T2 = 87°C
Specific heat = C = ?
Formula
Q = mC(T2 - T1)
- Solve for C
C = Q / m(T2 - T1)
- Substitution
C = 400 / 5.6 (87 - 23)
- Simplification
C = 400 / 5.6(64)
C = 400 / 358.4
- Result
C = 1.116 J/g°C
<h2>
Answer:</h2>
44.06 g/mol
<h3>
Explanation:</h3>
We are given;
- Number of moles of unidentified gas as 1.674×10^-4 mol
- Time of effusion of unidentified gas 86.6 s
- Number of moles of Argon gas as 1.715×10^-4 mol
- Time of effusion of Argon gas is 84.5 s
We are supposed to calculate the molar mass of unidentified gas
<h3>Step 1: Calculate the effusion rates of each gas</h3>
Effusion rate = Number of moles/time
Effusion rate of unidentified gas (R₁)
= 1.674×10^-4 mol ÷ 86.6 s
= 1.933 × 10^-6 mol/s
Effusion rate of Argon gas (R₂)
= 1.715×10^-4 mol ÷ 84.5 sec
= 2.030 × 10^-6 mol/s
<h3>Step 2: Calculate the molar mass of unidentified gas</h3>
- Assuming the molar mass of unidentified gas is x;
- We can use the Graham's law of effusion to find x;
- According to Graham's law of diffusion;

But, Molar mass of Argon is 39.948 g/mol
Therefore;


Solving for X
x = 44.06 g/mol
Therefore, the molar mass of the identified gas is 44.06 g/mol
Answer:
Scientists make improved explanations by building on old ideas and working with new data.
Explanation:
The right answer for the question that is being asked and shown above is that: "B 1.5 X 1-^-5 ppm." A 250-mL aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/mL. The concentration in ppm is that <span>1.5 X 1-^-5 ppm</span>
I think it's the Terminals