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Elena L [17]
4 years ago
8

A normal distribution has a mean of 50 and standard deviation of 5. Which value produces a negative z-score?​

Mathematics
1 answer:
zimovet [89]4 years ago
8 0

Answer:

x\:.

Step-by-step explanation:

The z-score for a normal distribution is calculated using the formula:

Z=\frac{x-\mu}{\sigma}.

From the question, the distribution has a mean of 50.

\implies \mu=50 and the standard deviation is \sigma=5.

For a z-score to be negative, then, \frac{x-\mu}{\sigma}\:.

\frac{x-50}{5}\:.

x-50\:.

x-50\:.

x\:.

\therefore x\:.

Any value less than 50 will produce a negative z-score

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When 0.5(20x – 50y + 36) – 0.25(–100x + 40y – 12) is simplified, what is the resulting expression?
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Answer:

<h2>35x - 35y + 21</h2>

solution,

0.5(20x - 50y + 36) - 0.25( - 100x + 40y - 12) \\  = 10x - 25y + 18  + 25x - 10y + 3 \\

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6 0
3 years ago
Evaluate f(x) when x=-10
adell [148]

Answer:

f(x) = 10(10)+3 = 103 when x = 10

Step-by-step explanation:

Given a function piecewise as

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We see from the definition of f(x) that the function has domain as (-3,13) and two sets defined from (-3,10) and [10,13).

Since 10 less than or equal to sign is there in the second function interval, we find that 10 is included in that.

Hence for finding f(10) we use the function defined for interval including 10 i.e. x^2+3

Substitute 10 for x in x^2+3

f(10) = 10^2+3

=103

Hence answer is 103

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