According to the Side Side Side postulate of congruent triangles, these triangles are congruent because each side is congruent to it’s corresponding side on the other triangle. When writing the congruence statement, you need to make sure that both triangles are read the same way so that one side corresponds to its congruent other side on the other triangle. One way to name these triangles would be HGK ≅ XWV
Answer:
In the graph we can find two points, lets select:
(2, 15) and (4, 30)
Those are the first two points.
Now, for two pairs (x1, y1) (x2, y2)
The slope of the linear equation y = s*x + b that passes trough those points is:
s = (y2 - y1)/(x2 - x1)
So the slope for our equation is
s = (30 - 15)/(4 - 2) = 15/2
then our linear equation is
y = (15/2)*x + b
now we can find b by imposing that when x = 2, y must be 15 (for the first point we selected)
15 = (15/2)*2 + b = 15 + b
b = 15 - 15 = 0
then our equation is:
y = (15/2)*x
Where we used a division and a multiplication.
The answer is 4/5 because there are 20 in total squared and circles but the total shapes is 25 so simplify the fraction 20/25=4/5
To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Answer:
Step-by-step explanation:
Given
Intersecting lines
Required
Find x
To do this, we make use of:
--- angle on a straight line
Collect like terms
Divide both sides by 3
