Rewrite the equation by completing the square. x^2 + 10x + 25 = 0
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<u>Given</u>:
Given that JKL is a right triangle.
The measure of ∠L is 90°
The length of JL = 24, LK = 7, and KJ = 25.
We need to determine the value of sine of ∠K.
<u>Value of sin ∠K:</u>
The value of sin ∠K can be determine using the trigonometric ratio.
Thus, we have;
Substituting , the side opposite to angle K is JL and the hypotenuse is JK
Thus, we have;
Substituting JL = 24 and JK = 25, we get;
Simplifying, we get;
Thus, the measure of sine of ∠K is 73.74°
