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avanturin [10]
2 years ago
10

Describe a circular cross-section of a sphere that does not pass through the center.

Mathematics
1 answer:
Mashutka [201]2 years ago
6 0

Answer:

The radius will be smaller than the radius of the sphere

The volume of the 2 pieces of the sphere will not be the same

Step-by-step explanation:

A sphere is a three-dimensional geometrical figure. It is a set of all points equidistant from a fixed point in space.

A circle is a two-dimensional figure. It is the locus of all points equidistant from a central point.

For a circular cross-section of a sphere that does not pass through the center,

the radius will be smaller than the radius of the sphere, the volume of the 2 pieces of the sphere will not be the same

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There are 1,198 souvenir paperweights that need to be packed in boxes. Each box will hold 12 paperweights. How many boxes will b
jasenka [17]

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100 boxes

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3 years ago
What is the explicit formula for the arithmetic sequence 2, 7, 12, 17,
Ray Of Light [21]

Answer:

x + 5

Step-by-step explanation:

Every time it goes up by a factor of 5

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3 years ago
What is the measure of XYZ, given that yz and xy are tangent to ?
Marta_Voda [28]

Answer:

D) 53 Degrees.

Step-by-step explanation:

Things we need to establish beforehand: We know that Lines OZ and OX are equal because they are both radii of the circle. We can make an Iscoceles traingle by drawing a line between ZX. We know angle YZO and angle YXO is a right angle because YZ and XY are tangent to the circle. The Arc angle is the same angle as angle ZOX.

1) Find angles OZX and OXZ. these will be 26.5, because 180-127 is 53, which is the sum of the two angles. the two angles are the same, so divide 53 by 2.

2) Find Angles XZY and ZXY. We know that YZO is a right angle, and both XZY and OZX make up this right angle so XZY + OZX = 90. OZX is 26.5, so 90-26.5=XZY. XZY = ZXY, so both angles equal 63.5.

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6 0
3 years ago
fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula
OleMash [197]
Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\

 A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\

 A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\

7 0
3 years ago
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