Question

F a shell can hold a maximum of 32 electrons, what is the value of n? 2 3 4 5

Answer 1

Answer: 4

Explanation:

Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n.

Azimuthal Quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number: This quantum number describes the orientation of the orbitals. It is represented as $m_l$. The value of this quantum number ranges from $(-l\text{ to }+l)$. When l = 2, the value of $m_l$ will be -2, -1, 0, +1, +2.

Given : a f subshell, thus l = 3 , Thus the subshells present would be 3, 2, 1, 0 and thus n will have a value of 4.

Also electrons give are 32.

The formula for number of electrons is $2n^2$.

$2n^2=32$

$n=4$

Thus principal quantum no will be n= 4.

Answer 2

Answer:

The shell which holds 32 electrons is fourth shell.

Explanation:

Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n.

Number of elections in nth shell is given by formula :$2n^2$

Number of electrons in ,n=1 : $2(1)^2=2$

Number of electrons in ,n=2 : $2(2)^2=8$

Number of electrons in ,n=3 : $2(3)^2=18$

Number of electrons in ,n=4 : $2(4)^2=32$

Number of electrons in ,n=4 : $2(5)^2=50$

The shell which holds 32 electrons is fourth shell.