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vladimir1956 [14]
3 years ago
12

Given the following rate equation, complete the sentences to identify the reaction order for each reagent, the overall reaction

order, and what effect doubling substance A and halving substance B would have on the overall rate of the process.
Rate= k[A] [B]^3

a. zero
b. first
c. second
d. third
e. fourth
f. remain the same as
g. be 1/4 of
h. be 1/2 of
i. be twice
j. be four times


1. Given the rate equation. the reaction order with respect to A is _________order
2. Given the rate equation, the reaction order with respect to B is _________ order
3. Given the rate equation. the overall reaction order I s________ order
4. Given the rate equation. when the concentration of A is doubled while that of B is halved, the rate will ________the original rate.
Chemistry
1 answer:
Eva8 [605]3 years ago
3 0

Answer:

1. First

2. Third

3. Fourth

4.remain the same as

Explanation:

Given the reaction equation;

Rate= k[A] [B]^3

We can see that the order of reaction is first order with respect to reactant A and third order with respect to reactant B. This gives an overall fourth order reaction.

If the concentration of A is doubled and that of B is halved. The rate of reaction remains the same.

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Help asap on a time crunch
marusya05 [52]

Answer:

<u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.

Correct answer - C

Explanation:

A solid sodium metal reacts with gaseous form of chlorine gas to form  a solid sodium chloride.

This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.

As a result, an ionic compound solid sodium chloride is formed.

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Therefore, <u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.

7 0
3 years ago
What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

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3 years ago
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