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vladimir1956 [14]
2 years ago
12

Given the following rate equation, complete the sentences to identify the reaction order for each reagent, the overall reaction

order, and what effect doubling substance A and halving substance B would have on the overall rate of the process.
Rate= k[A] [B]^3

a. zero
b. first
c. second
d. third
e. fourth
f. remain the same as
g. be 1/4 of
h. be 1/2 of
i. be twice
j. be four times


1. Given the rate equation. the reaction order with respect to A is _________order
2. Given the rate equation, the reaction order with respect to B is _________ order
3. Given the rate equation. the overall reaction order I s________ order
4. Given the rate equation. when the concentration of A is doubled while that of B is halved, the rate will ________the original rate.
Chemistry
1 answer:
Eva8 [605]2 years ago
3 0

Answer:

1. First

2. Third

3. Fourth

4.remain the same as

Explanation:

Given the reaction equation;

Rate= k[A] [B]^3

We can see that the order of reaction is first order with respect to reactant A and third order with respect to reactant B. This gives an overall fourth order reaction.

If the concentration of A is doubled and that of B is halved. The rate of reaction remains the same.

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what conclusions can be made about the relationship between metallic character and the atomic radius?
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HELP PLEASE! <br> Picture for question provided
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Answer:

Explanation:

The first one is CrO.  The Chromium has the same charge as the oxygen so mol numbers are dropped.

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A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
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The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

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q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

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