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lisov135 [29]
2 years ago
9

A car weighs 3.6 tons. Find its weight in pounds.

Mathematics
1 answer:
Assoli18 [71]2 years ago
3 0
The answer is 7,200 :)
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KengaRu [80]

The quadratic formula is \frac{-b+-\sqrt[2]{b^2-4ac}}{2a}

and in the equation ax^2+bx+c=0

so now all you have to do is substitute the numbers into the quadratic formula

7 0
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The graph shows the temperature throughout the day in a city in California, Is the relationship shown linear? Why or why not ?
Lera25 [3.4K]
No the graph is exponential
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Read 2 more answers
4 and 2/3 divided by 3/4 as a fraction
Bumek [7]

Answer:

dg

Step-by-step explanation:

7 0
2 years ago
The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
Tamiami turned in 6 homework assignments. if she turned in 75 percent of the homework assignments that were due how many homewor
vivado [14]
Percemt means parts out of 100
75%=75/100=15/20=3/4

turned in 6
if she turned in 3/4 of total assignments due then how many total?
6=3/4 times total
multily both sides by 4/3 to clear fraction
24/3=total
8=total
answer is 8 homeworks were assigned
5 0
3 years ago
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