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tekilochka [14]

3 years ago

13

If a wave has amplitude of 2 meters, a wavelength of 5 meters, and a frequency of 60 Hz, at what speed is it moving?

2 answers:

kow [346]3 years ago

6 0

Answer: The velocity is 300 meters per second.

Explanation: The velocity of a wave is related to the frequency and the wavelenght by the following equation:

velocity = frequency*wavelenght

or, using the formal notation;

v = f*λ

We know that f = 60Hz (and Hz is 1/s) and λ = 5m, so we have:

v = 5m*60(1/s) = 300m/s

klemol [59]3 years ago

5 0

The relationship between speed of a wave w, frequency f and wavelength $\lambda$ is
$v = \lambda f$
For the wave of our problem, $\lambda = 5 m$ and f=60 Hz, so its speed is
$v=(5 m)(60 Hz)=300 m/s$

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A wooden rod of negligible mass and length 80.0cm is pivoted about a horizontal axis through its center. A white rat with mass 0

algol13

Answer:

The speed of the animals is 1.64m/s.

Explanation:

Let us work with variables and call the mass of the two rats $m_1$ and $m_2$ , and the length of the rod $L$ .

Using the law of conservation of energy, which says the potential energies of the rats must equal their kinetic energies, we know that when the rod swings to the vertical position,

$m_1\frac{L}{2}g -m_2\frac{L}{2}g = \frac{1}{2}m_1v^2+\frac{1}{2}m_2v^2$

$(m_1 -m_2)g\frac{L}{2} = \frac{1}{2}(m_1+m_2)v^2$ ,

solving for $v$ , we get:

$\boxed{v = \sqrt{\frac{(m_1 -m_2)gL}{(m_1+m_2)}} }$

Putting in the values for $m_1$ , $m_2$ , $g$ , and $L$ we get:

$v = \sqrt{\frac{(0.450kg -0.220kg)(9.8m/s^2)(0.8m)}{(0.450kg+0.220kg)}}$

$\boxed{ v= 1.64m/s}$

Therefore, as the rod swings through the vertical position , the speed of the rats is 1.64 m/s.

7 0

2 years ago

Please answer these questions <br> 30 points

Maksim231197 [3]

Answer:

if i were you i would try to do the work because if you let someone else you wont be able to understand the question

6 0

2 years ago

Read 2 more answers

A rectangular coil of dimensions 5.40cm x 8.50cm consists of25 turns of wire. The coil carries a current of 15.0 mA.

Kazeer [188]

Answer:

(a) Magnetic moment will be $17.212\times 10^{-4}A-m^2$

(b) Torque will be $6.024\times 10^{-4}N-m$

Explanation:

We have given dimension of the rectangular 5.4 cm × 8.5 cm

So area of the rectangular coil $A=5.4\times 8.5=45.9cm^2=45.9\times 10^{-4}m^2$

Current is given as $i=15mA=15\times 10^{-3}A$

Number of turns N = 25

(A) We know that magnetic moment is given by $magnetic\ moment=NiA=25\times 45.9\times 10^{-4}\times 15\times 10^{-3}=17.212\times 10^{-4}A-m^2$

(b) Magnetic field is given as B = 0.350 T

We know that torque is given by $\tau =BINA=0.350\times 15\times 10^{-3}\times 25\times 45.9\times 10^{-4}=6.024\times 10^{-4}N-m$

4 0

2 years ago

Why in a rollercoaster the height of the tracks is either equal to or less than the first track

umka2103 [35]

Answer:

I really don't know

Explanation:

sorry

6 0

2 years ago

What device increases voltage?

erma4kov [3.2K]

Your answer would be C.

A step-up transformer is a transformer that raises voltage from main to secondary by having more secondary winding turns than primary winding turns.

Hope this helps; have a great day!

8 0

2 years ago