1 A
2 C
3 B
4 D
hope this helps your pal abigail
Answer:
(i) Electric field outside the shell:
For point r>R; draw a spherical gaussian surface of radius r.
Using gauss law, ∮E.ds=q0qend
Since E is perpendicular to gaussian surface, angle betwee E is 0.
Also E being constant, can be taken out of integral.
So, E(4πr2)=q0q
So, E=4πε01r2q
Answer:
The wavelength of the station’s signal is 2.9 meters
The energy of a photon of the station’s electromagnetic signal is 
Explanation:
Wavelength
is inversely proprtional to frequency (f) and directly proportional to velocity of the wave (v).
(1)
But electromagnetic waves as radio signals travel at speed of light so using this on (1):

Albert Einstein discovered that energy of electromagnetic waves was quantized in small discrete packages of energy called photons with energy:

with h the Planck's constant.
Its false I got It right .
Answer:
Tension, T = 2038.09 N
Explanation:
Given that,
Frequency of the lowest note on a grand piano, f = 27.5 Hz
Length of the string, l = 2 m
Mass of the string, m = 440 g = 0.44 kg
Length of the vibrating section of the string is, L = 1.75 m
The frequency of the vibrating string in terms of tension is given by :





T = 2038.09 N
So, the tension in the string is 2038.09 N. Hence, this is the required solution.