Answer:
1=false and 2=1st answer is correct
Answer:
a
![\theta = 23.32^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2023.32%5Eo%20)
b
![\mu_s = 0.27](https://tex.z-dn.net/?f=%20%5Cmu_s%20%3D%20%200.27%20%20)
c
![s = 0.948 \ m](https://tex.z-dn.net/?f=%20s%20%3D%20%200.948%20%5C%20%20m%20)
Explanation:
From the question we are told that
The mass of the bag is ![m_b = 25.0 \ kg](https://tex.z-dn.net/?f=m_b%20%20%3D%20%2025.0%20%5C%20%20kg)
The normal force experienced is ![F_n = 225 \ N](https://tex.z-dn.net/?f=F_n%20%20%3D%20%20225%20%5C%20N)
The maximum acceleration of the bag is ![a = 2.40 \ m/s^2](https://tex.z-dn.net/?f=a%20%3D%20%202.40%20%5C%20%20m%2Fs%5E2)
Generally this normal force experience by the bag is mathematically represented as
![F_n = mg cos \theta](https://tex.z-dn.net/?f=F_n%20%20%3D%20%20mg%20cos%20%5Ctheta)
=> ![225 = (25 * 9.8) cos \theta](https://tex.z-dn.net/?f=225%20%20%3D%20%20%2825%20%2A%209.8%29%20cos%20%5Ctheta)
=> ![0.9183 = cos \theta](https://tex.z-dn.net/?f=%200.9183%20%20%3D%20%20%20cos%20%5Ctheta)
=> ![\theta = cos^{-1}[0.9183]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20cos%5E%7B-1%7D%5B0.9183%5D)
=> ![\theta = 23.32^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2023.32%5Eo%20)
Generally for the bag not to slip , it means that the frictional force is equal to the sliding force
![F_f = F_s](https://tex.z-dn.net/?f=F_f%20%3D%20%20F_s)
Hence
is mathematically represented as
While
is mathematically represented as
![F_s = m * a](https://tex.z-dn.net/?f=F_s%20%20%20%3D%20%20m%20%2A%20a%20)
So
=>
=> ![\mu_s = 0.27](https://tex.z-dn.net/?f=%20%5Cmu_s%20%3D%20%200.27%20%20)
Generally from the workdone equation we have that
![KE_f - KE_i = W_f](https://tex.z-dn.net/?f=KE_f%20-%20KE_i%20%3D%20%20W_f)
Here
is the work done by friction which is mathematically represented as
Here s is the distance covered by the bag
is zero given that velocity at rest is zero
and
![KE_i = \frac{1}{2} * m* v_i^2](https://tex.z-dn.net/?f=KE_i%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20m%2A%20v_i%5E2)
so
![\frac{1}{2} * m* v_i^2 = m * g * \mu_k * s](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20m%2A%20v_i%5E2%20%3D%20m%20%2A%20g%20%2A%20%5Cmu_k%20%2A%20s%20)
=> ![\frac{1}{2} * v_i^2 = g * \mu_k * s](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20v_i%5E2%20%3D%20%20%20g%20%2A%20%5Cmu_k%20%2A%20s%20)
substituting 2.55 m/s for v_i and 0.350 for \mu_k we have that
![\frac{1}{2} * 2.55^2 = 9.8 * 0.350 * s](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%202.55%5E2%20%3D%20%20%209.8%20%2A%200.350%20%2A%20s%20)
=> ![s = 0.948 \ m](https://tex.z-dn.net/?f=%20s%20%3D%20%200.948%20%5C%20%20m%20)
Troposphere, stratosphere, mesosphere, thermosphere, exosphere
Answer:
I have examined the different parts of blub and I assume the answer is (D)T and U
Hope this helps you