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xeze [42]
4 years ago
9

How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?

Physics
1 answer:
V125BC [204]4 years ago
6 0

Explanation:

<u>Mass of car</u> = 137.5 kg

<u>Acceleration</u> = v - u / t = 26 - 0 / 6 = 4.33 m/sec^2

Force = m * a = 137.5 * 4.33 = 595.3 N

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A boat is traveling at a speed of 36 km/h. It has to travel a distance of 210 km. How long will it take?
oksian1 [2.3K]

Answer:

If the boat is going 36 km/h, then it will take about 5.8 hours to travel a distance of 210 km/h.

Explanation:

To calculate time, you have to divide the distance by the speed.

In this case, we take 210 and divide it by 36. The answer you will get is 5.83...

6 0
3 years ago
Read 2 more answers
You are looking down on a 20 kg beam resting on a horizontal, frictionless surface. The beam is 2 m long and can pivot about one
Korolek [52]

The angular speed of the rod after the impact is 1.49 rad/s

What is angular speed?

The rate of change of angular displacements is known as angular speed.

Angular speed is a scalar measure of the rotating object.

What is Angular momentum?

It is the property of a rotating body given by the product of the moment of inertia and the angular velocity of the rotating object.

Angular momentum is expressed as follows:

L=m*v*r

Here,

mass of beam, M =20 kg

mass of rock, m =0.1 kg

length of the beam, L =2 m

length where rock slides, l = (L / 2), l = 1 m

velocity of rock, v =400 m/s

As here the Torque on which the system is zero implies that the angular momentum is conserved.

Initial angular momentum for rock: I(ri) = m*v*r

Final angular momentum for rock: I(rf) = m*w*r^2

Final angular momentum for beam: I(bf) = 1/3 (M*L^2w)

Now, According to the conservation of momentum:

m*v*r =  m*w*r^2 +  1/3 (ML^2w)

w = m*v*r / ( mr^2 + 1/3 ML^2 )

w = 0.1 *400*1 / ( (0.1 * 1) + 1/3 20* 2^2 )

w = 1.49 rad / s

The angular speed of the rod after the impact is 1.49 rad/s

Learn more about Angular speed here:

<u>brainly.com/question/14663644</u>

#SPJ4

6 0
2 years ago
What components of an ecosystem do organism respond to
sweet [91]
All components, Abiotic to Biotic
7 0
3 years ago
HELP NEEDED! Determine the mechanical energy of this object: a 1-kg ball rolls on the ground at 2 m/s.
valentina_108 [34]
The mechanical energy of an object is the sum of its potential and kinetic energy.

Because the ball is on the ground, its potential energy is 0.
Its kinetic energy is given by:

K.E = 1/2 mv²
K.E = 1/2 x 1 x 2²
K.E = 2 J

Mechanical energy = 2 + 0
Mechanical energy = 2 J

The answer is B.
4 0
4 years ago
Read 2 more answers
A 1200 Kg car rounds a corner of radius r = 45m. If the coefficient of static friction between the ties and the road is us = 0.8
Vaselesa [24]

Answer:

The greatest speed of the car is 19.36m/s

Explanation:

The maximum speed the car will attain without skidding is given by:

F= uN = umg ...eq1

But F = mv^2/r

mv^2/r = umg

Dividing both sides by m, leaves you with:

V= Sqrt(ugr)

Where u = coefficient of static friction

g = acceleration due to gravity

r = raduis

Given:

U = 0.82

r=0.82

g= 9.8m/s

V = Sqrt(0.82 × 9.8 × 45)

V = Sqrt(374.85)

V = 19.36m/s

5 0
4 years ago
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