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2 years ago

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Leon is going to toss two number cubes, each labeled 1-6. What is the probability that Leon will toss a sum of 6? 1 /1 2, 1/6, 1

/9, or 5/36

1 answer:

Inessa05 [86]2 years ago

4 0

Answer:

Step-by-step explanation:

5/36

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Help me plsss!! Thank youuuu.

Andru [333]

Answer:

The answer is B.

Step-by-step explanation:

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3 years ago

Consider the intersecting lines shown. Which of the following statements is true?

elixir [45]

Answer:

C. m∠x + m∠y = 180

Step-by-step explanation:

The two straight line in the diagram intersect each other to form two pairs of vertical angles. These are <x and <z, and <y and w.

The only statement from the given options that is true is m∠x + m∠y = 180.

This is because they are angles in a straight line. The sun of angles in a straight line is 180°.

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3 years ago

Please help me! I will mark brainliest!

Elenna [48]

Answer:

Your picture didn't load?

Step-by-step explanation:

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3 years ago

Many bank accounts never go below zero. But some banks will allow a negative balance, at least for a short time, called an overd

Sergio039 [100]

Answer:

the amount after 3 weeks is $37.33

Step-by-step explanation:

Given that

His balance is -$48.82 i.e. overdraft

Now in order to get the positive balance, he plans to deposit the money of $28.55 per week

We need to find out the amount after 3 weeks

So,

= -$48.32 + $28.55 + $28.55 + $28.55

= $37.33

hence, the amount after 3 weeks is $37.33

3 0

3 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago