When 80.0 grams of calcium chloride react with silver nitrate, how many grams of silver

Chemistry

1 answer:

hichkok12 [17]3 years ago

5 0

Answer:

Mass = 206.38 g

Explanation:

Given data:

Mass of calcium chloride = 80.0 g

Mass of silver chloride formed = ?

Solution:

Chemical equation:

CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl

Number of moles of CaCl₂:

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 110.98 g/mol

Number of moles = 0.72 mol

Now we will compare the moles of CaCl₂ and AgCl

CaCl₂ : AgCl

1 : 2

0.72 : 2/1×0.72 = 1.44 mol

Mass of silver chloride:

Mass = number of moles × molar mass

Mass = 1.44 mol × 143.32 g/mol

Mass = 206.38 g

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