The bowl of mixed fruits is a mixture because there are several things making up the object. Hence, option (B) is correct.
What is a mixture?
- The matter is categorized as mixtures and pure substances.
- A mixture is defined as a combination of substances that are not chemically mixed.
- A mixture can exist in solid, liquid, or gas form.
- A mixture can exist in the same or in a different phase. It can be homogenous or heterogeneous.
- If the substances are combined in the same phase, then the mixture is a homogeneous mixture.
- But if the substances are combined in different phases, then it is a heterogeneous mixture.
Therefore, the mixed fruit bowl is a mixture, because there are several things making up the object.
Hence, option (B) is correct.
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Answer:
Age of rock = 6.12 × 10³ years
Note: The question is incomplete.A similar but complete question is given below.
The half-life for the radioactive decay of carbon-14 to nitrogen-14 is 5.73 x 10^3 years. Suppose nuclear chemical analysis shows that there is 0.523mmol of nitrogen-14 for every 1.000 mmol of carbon-14 in a certain sample of rock.
Calculate the age of the rock. Round your answer to 2 significant digits.
Explanation:
The half-life of a radioactive material is the time taken for half the atoms in the atomic nucleus of a material to disintegrate.
The half-life for the radioactive decay of carbon-14 to nitrogen-14 is given as 5.73 x 10³ years. This means that given 1 mole of carbon-14 is present initially, after one half-life, 0.5 moles of carbon-14 would remain.
Number of millimoles of carbon-14 remaining = 1 - 0.523 = 0.477 mmol
Number of half-lives that the carbon-14 has undergone is determined as follows:
Amount remaining = (1/2)ⁿ
where nnis number of half-lives
0.5 mmol = one half-life
0.5 = (1/2)¹
O.477 = (1/2)ⁿ = (0.5)ⁿ
㏒₀.₅(0.477) = n
n = ㏒(0.477)/㏒(0.5)
n = 1.067938829
Age of the rock = number of half-lives × half-life
Age of rock = 1.067938829 × 5.73 × 10³ years
Age of rock = 6.12 × 10³ years
<u>Answer:</u> The value of 
for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K
<u>Explanation:</u>
Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate entropy change is of a reaction is:
![\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
The equation for the entropy change of the above reaction is:
![\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20S%5Eo_%7B%28HF%28g%29%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20S%5Eo_%7B%28H_2%28g%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20S%5Eo_%7B%28F_2%28g%29%29%7D%29%5D)
We are given:
Putting values in above equation, we get:
![\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%28173.78%29%29%5D-%5B%281%5Ctimes%20%28130.68%29%29%2B%281%5Ctimes%20%28202.78%29%29%5D%5C%5C%5C%5C%5CDelta%20S%5Eo_%7Brxn%7D%3D14.1J%2FK)
Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K
We are given:
Moles of hydrogen gas reacted = 2.20 moles
By Stoichiometry of the reaction:
When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K
So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = 
Hence, the value of for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K
At a constant temperature and pressure, liquids retain their volume
Answer:
≈170.22 [gr].
Explanation:
1) M(Cu₂CO₃)=2*64+12+3*16=188 [gr/mol];
2) the part of copper in Cu₂CO₃ is:
3) 16/47% of 500 [gr] is:
![500*\frac{16}{47}=170.22[gr].](https://tex.z-dn.net/?f=500%2A%5Cfrac%7B16%7D%7B47%7D%3D170.22%5Bgr%5D.)
