Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
Explanation:
Given:
= 61 L,
= 183 K,
= 0.60 atm
At STP, the value of pressure is 1 atm and temperature is 273.15 K.
Now, formula used to calculate the new volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
<span>We are given the initial amount of 1 million carbon-14 atoms and the final amount which is 1/16 of the current atmospheric 14C levels. Also, the half life of carbon is </span>5,750 years. WE can use the decay formula
Aₓ = A₀e^-(ln2/t1/2)t
1,000,000(1/16) = (1,000,000)e^-(ln2/5750)t
t = 23,000 years
A lower pH means that there are extra hydrogen ions in the liquid, whereas a higher pH indicates fewer hydrogen ions in the liquid. In simple terms, pH is a scale from 1 to 14 that measures the acidity or alkalinity of a liquid.
The hydrated ion undergoes hydrolysis in solution producing `H3O+ . This occurs because the Be-O bond is very strong and so in the hydrated ion and it weakens the 0-H bond. Hence, there is a strong tendency to lose protons. For this particular reason, the aqueous solution of `BeCl_2` is acidic in nature.
<h3>Will baking soda decrease pH?</h3>
Baking soda, also regarded as sodium bicarbonate is naturally alkaline, with a pH of 8 When you add baking soda to your pool water, you will increase both the pH and the alkalinity, improving balance and clarity. Many industrial pool merchandise for elevating alkalinity utilize baking soda as their most important active ingredient.
Learn more about pH here:
<h3>
brainly.com/question/22390063</h3><h3 /><h3>#SPJ4</h3>
Answer : The molar mass of the solute will be
87.90 g/mol.Explanation : We know the formula for elevation in boiling point, which is
Δt = i

m
given that, Δt = 0.357,

= 5.02 and mass of

= 40,
on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X

.
Now, 0.250/ 2.844 X

=
87.90 g/mol. which is the weight of unknown component.