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kaheart [24]
3 years ago
12

The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

Option A.

Step-by-step explanation:

It is given that the smallest of 6 consecutive integers is p. So, all numbers are

p,p+1,p+2,p+3,p+4,p+5

The greatest is q.  

q=p+5

Now, the value of the average of p and q in terms of p is

Average=\dfrac{p+q}{2}

Average=\dfrac{p+p+5}{2}

Average=\dfrac{2p+5}{2}

Average=\dfrac{2p}{2}+\dfrac{5}{2}

Average=p+2.5

Therefore, the correct option is A.

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