Given:
ΔV = 5 - 1.48 L = 3.52 L = 0.00352 m³, th chane in volume
p = 0.818 atm = 0.819*101325 Pa = 82985.2 Pa

By definition, the work done is
$W = \int pdV = (82985.2 \, \frac{N}{m^{2}} )*(0.00352 \, m^{3}) = 292.1 \, J$

Answer: 292.1 J

5 0

3 years ago

What is the oxidation number for as in as2o3?

Mekhanik [1.2K]

Ok so O3 has a greater electronegativity and is taken into account first, -2*3=-6, so As has to equal 6/2=3, so As has a +3 oxidation number here

8 0

3 years ago

Read 2 more answers

A chemist measures the amount of fluorine gas produced during an experiment. He finds that 482. g of fluorine gas is produced.

nata0808 [166]

Answer: 25.37055324733817mol

Approximately 25.371mol

Explanation: Number of moles of a substance is the mass of that substance containing the same amount of fundamental units, for instance atom in 12.0g of 12°C

Therefore:

Number of moles= mass/ molecular mass

Where mass of fluorine given= 482g

Standard Molecular mass of fluorine= 18.9984032g/mol

Substituting value in equation

Mole= 482g/18.9984032g/mol = 25.37055324733817mol

Approximately : 25.371mol

4 0

3 years ago