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3 years ago

Which of these is a behavioral adaptation?

Chemistry

2 answers:

Yuki888 [10]3 years ago

6 0

Answer: D :a brown bear hibernates and becomes inactive during winter.

Explanation:

TiliK225 [7]3 years ago

5 0

The answer should be (D)

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I need help with question 4

meriva

The bat in my opinion...

3 0

3 years ago

Read 2 more answers

Let’s say that you have a solvatochromic compound that appears red in a solvent. You dissolve the compound in another solvent an

EastWind [94]

Answer:

Hypsochromic compound, More polar solvent

Explanation:

Hypsochromic shift refers to the shift of solution colour to blue side of the visible spectrum (blueshift) with increasing polarity of the solvent. In our case, the solution changes to orange colour from red when solvent is changed. This means that the emission spectrum of the solution underwent blueshift. (As orange colour is on the 'blue' side for red colour.) So this is a hypsochromic shift, and the new solvent is more polar that the previous one, as it caused hypsochromic shift.

7 0

3 years ago

Elements that can be described by the hardness shininess and ductility

Eddi Din [679]

Metals. Titanium is very hard, gold is shiny, and copper is ductile(can be pulled into a wire without breaking). <span />

6 0

3 years ago

Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the

daser333 [38]

Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.

Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.

From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.

Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.

Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position

Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.

Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

4 0

3 years ago

A certain radioactive isotope decays at a rate of 0.2% annually. Determine the half-life of this isotope, to the nearest year

pychu [463]

Answer:

The half-life of the radioactive isotope is 346 years.

Explanation:

The decay rate of the isotope is modelled after the following first-order linear ordinary differential equation:

$\frac{dm}{dt} = -\frac{m}{\tau}$

Where:

$m$ - Current isotope mass, measured in kilograms.

$t$ - Time, measured in years.

$\tau$ - Time constant, measured in years.

The solution of this differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope. It is known that radioactive isotope decays at a yearly rate of 0.2 % annually, then, the following relationship is obtained: