Answer:
Value = 1.80 g/cm³ (Approx)
Explanation:
Given:

Computation:

Value = 1.80 g/cm³ (Approx)
I think it’s 2 hope that helped
The volume : 8,526 quarts
<h3>Further explanation</h3>
Given
The density of whole milk = 1.04 g/ml
mass = 18.5 pounds
Required
The volume
Solution
Conversion of mass
1 pound = 453,592 g
18.5 pounds = 8391,45 g
Density formula:
.
Input the value :
V = m : ρ
V = 8391,45 g : 1.04 g/ml
V = 8068.7 ml
1 ml = 0,00105669 quarts
8068.7 ml =8,526 quarts
Answer:
V=0.3×22.4=6.72 liters hope this helps
<u>The addtion of energy</u> <span>is usually needed to help a decomposition reaction occur</span>