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Ipatiy [6.2K]
4 years ago
10

Which mineral is commonly found in igneous rocks? halite feldspar gypsum talc

Chemistry
2 answers:
pochemuha4 years ago
7 0

Answer:

feldspar

Explanation:

just learned about this :)

erik [133]4 years ago
6 0

Answer:

Feldspars

Explanation:

Hope this helps! :) x

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What is the center of a plant cell? The actual question is what’s the center of an onions root tip?
klasskru [66]
The center of a plant cell is a nucleus!
4 0
4 years ago
Read 2 more answers
A) If Kb for NX3 is 4.5×10^−6, what is the pOH of a 0.175 M aqueous solution of NX3 ?
sukhopar [10]

3.08 is the pOH of a 0.175 M aqueous solution of NX_3.

0.215% is the per cent ionization of a 0.325 M aqueous solution of NX_3

<h3>What is pH?</h3>

pH is a measure of how acidic/basic water is.

A)

NX_3 + H_2O →NHX_3^+ + OH^-

Kb = 4.5 x10^-6

Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).

concentration of (NH₄⁺) = concentration of (OH⁻) = x.

x² = Kb x concentration of (NH₃)

x² = 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)

= 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

=- log ( 8.367 × 10⁻⁴)

= 3.08

B)

Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.

Concentration of (NX₃) = 0.325 M.

Kb = 4.5 x 10⁻⁶.

[NX₃H⁺] = [OH⁻] = x.

[NX₃] = 0.325 M - x.

Kb = [NX₃H⁺] x [OH⁻] ÷  [NX₃].

4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).

x = 0.0007 M.

Per cent of ionization:

α = 0. 0007 M ÷ 0. 325 M x 100%

= 0.215%.

Hence,

3.08 is the pOH of a 0.175 M aqueous solution of NX_3.

0.215% is the per cent ionization of a 0.325 M aqueous solution of NX_3

Learn more about pH here:

brainly.com/question/12353627

#SPJ1

5 0
2 years ago
Which describes a step in the process of forming an ionic bond?
creativ13 [48]

Answer:

A metal atom loses electrons and becomes a positive ion and a non-metal atom gains electrons and becomes a negative ion.

3 0
3 years ago
If you have 100 grams of a chemical with a half-life of 8 days, then how much will you have after 40 days?
dedylja [7]

Answer:

option d = 3.125 g

Explanation:

Given data:

Mass of chemical = 100 g

Half life = 8 days

mass left after 40 days = ?

Solution:

First of all we will calculate the total half life's,

half life's = T (elapsed) / T half life

half life's = 40 / 8 = 5

starting mass = 100 g

  half life's         1           2          3             4               5

 Mass             100/2    50/2      25/2       12.5/2       6.25/2

                         50 g        25 g        12.5 g      6.25 g        3.125 g

 

8 0
4 years ago
What is the ph of a 0.001 62 m naoh solution?
marin [14]
The answer 
first of all, we should know that NaOH is a strong base. For such a product, the conentration of the OH -  is equivalent to the concentration of the NaOH itself.
that means:
[ OH -] = [ NaOH] =<span>0.001 62 
and for a strong basis, pH can be calculated as pH = 14 + log </span>[ OH -] 
first we compute log [ OH -] :
log [ OH -] = log (0.001 62)= -2.79

finally pH = 14 -2.79 = 11.20
4 0
3 years ago
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