Answer:
Value = 1.80 g/cm³ (Approx)
Explanation:
Given:
![\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3}](https://tex.z-dn.net/?f=%5Cfrac%7B3.39%20%5Ctimes%2010%5E7g%7D%7B%28%5Cfrac%7B4%7D%7B3%7D%20%29%283.1416%29%281.65%20%5Ctimes%2010%5E2%20cm%29%5E3%7D)
Computation:
![\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(1.65 \times 10^2 cm)^3} \\\\\frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)} \\\\ \frac{3.39 \times 10^7g}{(\frac{4}{3} )(3.1416)(4.492125 \times 10^6 cm^3)}\\\\ \frac{3.39 \times 10^7g}{18.8166132\times 10^6 cm^3} \\\\ 1.80159945g/cm^3](https://tex.z-dn.net/?f=%5Cfrac%7B3.39%20%5Ctimes%2010%5E7g%7D%7B%28%5Cfrac%7B4%7D%7B3%7D%20%29%283.1416%29%281.65%20%5Ctimes%2010%5E2%20cm%29%5E3%7D%20%5C%5C%5C%5C%5Cfrac%7B3.39%20%5Ctimes%2010%5E7g%7D%7B%28%5Cfrac%7B4%7D%7B3%7D%20%29%283.1416%29%284.492125%20%5Ctimes%2010%5E6%20cm%5E3%29%7D%20%5C%5C%5C%5C%20%5Cfrac%7B3.39%20%5Ctimes%2010%5E7g%7D%7B%28%5Cfrac%7B4%7D%7B3%7D%20%29%283.1416%29%284.492125%20%5Ctimes%2010%5E6%20cm%5E3%29%7D%5C%5C%5C%5C%20%5Cfrac%7B3.39%20%5Ctimes%2010%5E7g%7D%7B18.8166132%5Ctimes%2010%5E6%20cm%5E3%7D%20%5C%5C%5C%5C%201.80159945g%2Fcm%5E3)
Value = 1.80 g/cm³ (Approx)
I think it’s 2 hope that helped
The volume : 8,526 quarts
<h3>Further explanation</h3>
Given
The density of whole milk = 1.04 g/ml
mass = 18.5 pounds
Required
The volume
Solution
Conversion of mass
1 pound = 453,592 g
18.5 pounds = 8391,45 g
Density formula:
.
Input the value :
V = m : ρ
V = 8391,45 g : 1.04 g/ml
V = 8068.7 ml
1 ml = 0,00105669 quarts
8068.7 ml =8,526 quarts
Answer:
V=0.3×22.4=6.72 liters hope this helps
<u>The addtion of energy</u> <span>is usually needed to help a decomposition reaction occur</span>