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2 years ago

Does anyone know how to do this?

Chemistry

1 answer:

o-na [289]2 years ago

3 0

Answer:

nop sorry

Explanation:

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Which statement describes the energy changes that occur as bonds are broken and formed during a chemical reaction? 1.Energy is a

Snowcat [4.5K]

Answer:

Explanation:

Br + Br-> Br2 (covalent bond)

bond formation releases energy, as the Br's are in a lower energy state like Br2

6 0

3 years ago

Which equation demonstrates that nuclear fusion forms elements that are heavier than helium

GrogVix [38]

Answer: The correct option is 2.

Explanation: There are two types of nuclear reactions:

1) Nuclear fission: These reactions are defined as the reactions in which a heavier unstable nuclei breaks into two or more smaller stable nuclei.

2) Nuclear fusion: These reactions are the ones where two smaller nuclei fuse together or combine together to form a larger nuclei.

In the question, we need to find the fusion reaction which forms elements heavier than helium.

Option 1: In this fusion reaction occurs but the nuclei is Helium itself.

Option 2: In this also fusion reaction occurs and the nuclei is heavier than Helium which is Neon.

$_8^{16}\textrm{O}+_2^4\textrm{He}\rightarrow _{10}^{20}\textrm{Ne}$

Option 3 and Option 4: These two reactions are nuclear fission reactions of Uranium-235 because one heavier element is breaking into more than 2 products.

Hence, the correct option is 2.

8 0

2 years ago

Read 2 more answers

During a total solar eclipse, the Earth, Sun, and Moon are arranged in a line, and almost all of the Sun's light traveling to th

Flauer [41]

The answer would be A

5 0

3 years ago

Read 2 more answers

Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?

TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

$2Al+6HBr\rightarrow 2AlBr_3+3H_2$

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

$8molAl(\frac{6molHBr}{2molAl})$

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

7 0

3 years ago

5.2 X 1026 molecules of CH4

olya-2409 [2.1K]

<h3 /><h3>Answer above </h3>

I cant send this with no text 

Have a nice day

8 0

2 years ago