Answer:
The work done on the system is -616 kJ
Explanation:
Given;
Quantity of heat absorbed by the system, Q = 767 kJ
change in the internal energy of the system, ΔU = +151 kJ
Apply the first law of thermodynamics;
ΔU = W + Q
Where;
ΔU is the change in internal energy
W is the work done
Q is the heat gained
W = ΔU - Q
W = 151 - 767
W = -616 kJ (The negative sign indicates that the work is done on the system)
Therefore, the work done on the system is -616 kJ
Answer:
The change in volume is
Solution:
As per the question:
Coefficient of linear expansion of Copper,
Initial Temperature, T = = 273 K
Final Temperature, T' = = 273 + 100 = 373 K
Now,
Initial Volume of the block, V =
where
V' = Final volume
Answer:
Explanation:
Given
mass of sled =26 kg
coefficient of static friction
coefficient of kinetic friction
In order to move sled from rest we need to provide a force greater than static friction which is given by
After Moving Sled kinetic friction comes in to play which is less than static friction
therefore minimum force to keep moving sledge at constant velocity is 18.34 N
1 mile. Is this a joke lol