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mars1129 [50]
4 years ago
12

Examine the scenario. Object A has 5 protons and 5 electrons. Object B has 5 protons and 7 electrons. Which option most accurate

ly describes the net charge on the two objects?
Object A has a net charge of -5 because it has 5 electrons. Object B has a net charge of –7 because it has 7 electrons.
Object A has a net charge of 0 because the positive and negative charges are balanced. Object B has a net charge of +2 because there is an imbalance of charged particles.
Object A has a net charge of +5 because it has 5 protons. Object B has a net charge of +5 because it has 5 protons.
Object A has a net charge of 0 because the positive and negative charges are balanced. Object B has a net charge of –2 because there is an imbalance of charged particles.
Physics
1 answer:
Travka [436]4 years ago
4 0
<span>Last choice on the list:
Object A has a net charge of 0 because the positive and negative
charges are balanced.
Object B has a net charge of –2 because there is an imbalance of
charged particles (2 more negative electrons than positive protons).</span>
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You are fixing a transformer for a toy truck that uses an 8.0-V emf to run it. The primary coil of the transformer is broken; th
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Answer:

a. The primary turns is 60 turns

b. The secondary voltage will be 360 volts.

Explanation:

Given data

secondary turns N2= 40 turns

primary turns N1= ?

primary voltage V1= 120 volts

secondary voltage V2= 8 volts

Applying the transformer formula which is

\frac{N1}{N2} =\frac{V1}{V2}

we can solve for N1 by substituting into the equation above

\frac{N1}{40} =\frac{120}{8} \\\ N1= \frac{40*120}{8} \\\ N1= \frac{4800}{8} \\\ N1= 60

the primary turns is 60 turns

If the primary voltage is V1 240 volts hence the secondary voltage V2 will be (to get the voltage of the secondary coil using emf substitute the values of the previously gotten N1 and N2 using V1 as 240 volts)

\frac{40}{60} =\frac{240}{V2}\\\\V2= \frac{60*240}{40} \\\\V2=\frac{ 14400}{40} \\\\V2= 360

the secondary voltage will be 360 volts.

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3 years ago
How many electrons circulate each second through the cross section of a conductor, which has a current intensity of 4A.
guajiro [1.7K]

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2.5×10¹⁹

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4 C/s × (1 electron / 1.60×10⁻¹⁹ C) = 2.5×10¹⁹ electrons/second

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Application of surface tension:
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2 years ago
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
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Answer:

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Given;

initial velocity, u = 60 km per hour

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initial time = 1 hour

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The average velocity is given by;

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I think its either C or D.

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