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Rainbow [258]
2 years ago
15

The moon Ariel orbits Uranus at a distance of 1.91 x 108 m once every 2.52 days. Use that data to calculate the mass of Uranus.

[?] x 10kg​
Physics
1 answer:
PIT_PIT [208]2 years ago
4 0

Mu = 8.66 × 10^25 kg

Explanation:

centripetal force = gravitational force

m \frac{ {v}^{2} }{r}  = (grav.const) \frac{m \times mu}{ {r}^{2} }

where

m = mass of moon Ariel

mu = mass of Uranus

r = radius of Ariel's orbit

v = Ariel's velocity around Uranus

To find the velocity, we need to find the circumference of the no orbit and then divide it by the period (2.52 days):

circumference = 2πr = 2π×(1.91 × 10^8 m)

= 1.2 × 10^9 m

period = 2.52 days × (24 h/1 day)×(3600 s/1 hr)

= 2.18 × 10^5 s

v = (1.2 × 10^9 m)/(2.18 × 10^5 s)

= 5.5 × 10^3 m/s

(5.5 × 10^3 m/s)^2/(1.91 × 10^8 m) = (6.67 × 10^-11 m^3/kg-s^2)Mu/(1.91 × 10^8 m)^2

Solving Mu,

Mu = 8.66 × 10^25 kg

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aksik [14]

Answer :

(a). The speed of the block is 0.395 m/s.

(b). No

Explanation :

Given that,

Diameter = 20.0 cm

Power = 26.0 MW

Mass = 110 kg

diameter = 20.0 cm

Distance = 100 m

We need to calculate the pressure due to laser

Using formula of pressure

P_{r}=\dfrac{I}{c}

P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}

P_{r}=2.75\ N/m^2

We need to calculate the force

Using formula of force

F=P\times A

F=P\times \pi r^2

Put the value into the formula

F=2.75\times\pi (0.01)^2

F=0.086\ N

We need to calculate the acceleration

Using formula of force

F=ma

Put the value into the formula

0.086=110\times a

a=\dfrac{0.086}{110}

a=0.000781\ m/s^2

a=7.81\times10^{-4}\ m/s^2

(a). We need to calculate speed of the block

Using equation of motion

v^2=u^2+2ad

Put the value into the formula

v=\sqrt{2\times7.81\times10^{-4}\times100}

v=0.395\ m/s

(b). No because the velocity is very less.

Hence, (a). The speed of the block is 0.395 m/s.

(b). No

8 0
2 years ago
A 912-kg car is being driven down a straight, level road at a constant speed of 31.5 m/s. When the driver sees a police cruiser
sergejj [24]

Answer:

786.6 N

Explanation:

mass of car, m = 912 kg

initial velocity of car, u = 31.5 m/s

final velocity of car, v = 24.6 m/ s

time, t = 8 s

Let a be the acceleration of the car

Use first equation of motion

v = u + a t

24.6 = 31.5 + a x 8

a = - 0.8625 m/s^2

Force, F = mass x acceleration

F = 912 x 0.8625

F = 786.6 N

Thus, the force on the car is 786.6 N.

8 0
2 years ago
True or false? All waves need a medium in order to travel
Art [367]
That's false.  Mechanical waves (like sound and ocean waves) do
need a medium to travel in, but electromagnetic waves (like radio
and light) don't.
4 0
3 years ago
Read 2 more answers
1. Choose the correct answer 1. Casparian strips are present in the of the root. a) cortex b) pith c) pericycle d) endodermis 2.
zloy xaker [14]

Answer:

1 casparian strips are present in the root of endodermis.

2 the endarch condition is the character fature of stem.

4 0
2 years ago
If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

5 0
3 years ago
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