Answer:
F = F2 - F1 where F is the net force upwards
F = 5 - (.5 * 9.8) = (5 - 4.9) N = .1 N
Since there is a net force in the upwards direction the rocket should experience an upwards acceleration.
The average velocity of the object in moving from point-B to point-C is
(the straight-line distance and direction from point-B to point-C)
divided by
(the time the object takes to make the trip) .
Answer:
7212.3 N
Explanation:
F = 7.38 x 10^4 N, v = 36.2 m/s
Let b be the strength of magnetic field and charge on the particle is q.
F = q v B Sin theta
Here theta = 90 degree
7.38 x 10^4 = q x 36.2 x B x Sin 90
q B = 2038.7 .....(1)
Now, theta = 17 degree, v = 12.1 m/s
F = q v B Sin theta
F = 2038.7 x 12.1 x Sin 17 ( q v = 2038.7 from equation (1)
F = 7212.3 N
Answer:
Explanation:
Since the surface is frictionless, momentum will be conserved. If the bullet of mass 
has an initial velocity 
and a final velocity 
and the block of mass 
has an initial velocity 
and a final velocity 
then the initial and final momentum of the system will be:
Since momentum is conserved, 
, which means:
We know that the block is brought to rest by the collision, which means 
and leaves us with:
which is the same as:
Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:
So kinetic energy of the bullet as it emerges from the block will be:
Answer:
the SI unit of momentum is :- kg.ms-1
and we know that,
kinetic energy = 1/2 mv2
E=p2/2m
p=(2Em)1/2
so the derived units are (J.kg)1/2
Explanation:
