Answer:
Incomplete question,
This is the complete question
Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same amount of force even after it starts moving. Find the acceleration ~a of the block after it begins to move. Express your answer in terms of some or all of the variables µs, µk, and m, as well as the acceleration due to gravity g.
Explanation:
Let the force that make the object to start moving be F,
Frictional force is opposing the motion, the body has to overcome two frictional forces acting in the opposite direction of the motion.
Also, weight and normal reaction are acting in vertical direction, the weight is acting downward while the reaction is acting upward.
Weight of the object is given as
W=mg
Analyzing the vertical motion i.e y-axis.
ΣF = ma
since the body is not moving upward, the a=0
N-W=0
Then, N=W
So, N=mg
So, from friction law
Fr=µN
For static
Fs=µsN
For kinetic or dynamic
Fk= µkN
Using newton law
Along x-axis
Before the body start moving we can get the Force and since the force is the same use to start the block in motion.
Then,
ΣF = ma
Since at static the body is not moving then, a=0
F-Fs=0
F=Fs
Since, Fs=µsN
F=Fs=µsN
Then, the force to keep the body in motion too is F=µsN
Now analyses when the body is in motion
ΣF = ma
F-Fk=ma
ma=F - Fk
Substituting F=µsN and Fk=µkN
ma=µsN - µkN
ma=N(µs - µk)
Since N=mg
Then, ma=mg(µs - µk)
m cancels out, then
a=g(µs - µk)
Then the acceleration of the body is given as "a=g(µs - µk)"
