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denis23 [38]
3 years ago
6

Which equation has a graph that is a parabola with a vertex at (5, 3)?

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

It is "A" or in other words the one that says (x-5)2+3 because when you graph it you can see it is the only one touching that point!

Step-by-step explanation:

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IF XPOWER 3 =27,THEN X POWER 2=
kvv77 [185]

X²= 9

X POWER 3= 27

X³= 27

The number that can be multiplied three times to get 27 is 3

Therefore X POWER 2 (X²) can be calculated as follows

= 3²

= 3 × 3

= 9

Hence XPOWER 2 is 9

Read more here

brainly.com/question/27510248?referrer=searchResults

#SPJ1

8 0
1 year ago
The question is in the picture, please help!!<br> a. (16/7 , 6/7)<br> b.(4 , 6/7)<br> c.( 2 , 6/7)
lianna [129]

Answer:

b.(4,6/7)

Step-by-step explanation:

i hope i was able to help with the question

4 0
2 years ago
Twenty eight slips of paper are numbered 1 through 28 and are distributed among a group of people. A random number generator is
Inessa05 [86]

Answer:

Option C is the correct answer.

Step-by-step explanation:

Since a random number generator is used to select a single number between 1 and 28, inclusively;

For a fair decision to be made during the process, the number of persons in the set must be a divisor of 28.

Let's list the divisors of 28:

The divisors of 28 are {1, 2, 4, 7, 14, 28}

The only option that contains one of the divisors is option C which is 7.

5 0
3 years ago
Jason knows that the equation to calculate the period of a simple pendulum is , where T is the period, L is the length of the ro
Brrunno [24]

<u>Answer-</u>

\boxed{\boxed{L=\dfrac{g}{4\pi^2 f^2}}}

<u>Solution-</u>

The equation for time period of a simple pendulum is given by,

T=2\pi \sqrt{\dfrac{L}{g}}

Where,

T = Time period,

L = Length of the rod,

g = Acceleration due to gravity.

Frequency (f) of the pendulum is the reciprocal of its period, i.e

f=\dfrac{1}{T}\ \Rightarrow T=\dfrac{1}{f}

Putting the values,

\Rightarrow \dfrac{1}{f}=2\pi \sqrt{\dfrac{L}{g}}

\Rightarrow (\dfrac{1}{f})^2=(2\pi \sqrt{\dfrac{L}{g}})^2

\Rightarrow \dfrac{1}{f^2}=4\pi^2 \dfrac{L}{g}

\Rightarrow L=\dfrac{g}{4\pi^2 f^2}

8 0
3 years ago
Read 2 more answers
Find the distance between the points (-5, 0) and (-4, 1).
choli [55]
The formula of a distance between two points A and B is : 

AB=\sqrt{(x_{B}- x_{A})^2 +( y_{B}- y_{A})^2     }

You should this formula by heart.

Then, you just have to apply it ! :D

Here :

x_{A}=-5
y_{A} =0

x_{B} =-4
y_{B}= 1

Therefore :

\sqrt{(-4-(-5))^2+(1-0)^2}
=  \sqrt{1^2+1^2}
= \sqrt{1+1}
= \sqrt{2}

In short, the answer would be the first option : \sqrt{2}.

Hope this helps !

Photon

6 0
3 years ago
Read 2 more answers
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