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3 years ago

Which question is a statistical question?

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

Answer:

A) How may students are in your math class?

This is because statistics are collecting How Many of something there is. If a question said: "How many people in your class are 5'2" that would be statistical.

kow [346]3 years ago

4 0

Answer:

Step-by-step explanation:

statistical should have data and numbers that can calculate

ex Mean, Med, Mode

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Please help me thanks

Alexxx [7]

Answer:

A. 1.609344 km

B. 0.62137119 m

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Jim is investing in the stock market. Jim is hoping to earn $2,000 in interest in order to take a trip to Mexico. Stock A earns

Vanyuwa [196]

Given:

Total amount for investment = $32000

Rate of interest for Stock A = 4%

Rate of interest for Stock B = 7%

Jim is hoping to earn $2,000 in interest.

To find:

The amount of investments in Stock A and Stock B.

Step-by-step explanation:

Let amount of investments in Stock A = $x

Amount of investments in Stock B = $y

Total amount for investment = $32000

$x+y=32000$ ...(i)

Rate of interests in Stock A and Stock B are 4% and 7%. Total interests is $2000.

$0.04x+0.07y=2000$ ...(ii)

From (i) and (ii), we get

$0.04x+0.07(32000-x)=2000$

$0.04x+2240-0.07x=2000$

$-0.03x=2000-2240$

$-0.03x=-240$

Divide both sides by -0.03.

$x=\dfrac{-240}{-0.03}$

$x=8000$

Put x=8000 in (i).

$8000+y=32000$

$y=32000-8000$

$y=24000$

Therefore, the amount of investments in Stock A and Stock B are $8000 and $24000 respectively.

8 0

3 years ago

Find the volume of a pyramid with a square base where the area of the base is 8.3 m 2 and the height of the pyramid is 9.8 m

borishaifa [10]

Answer:

245.56

Step-by-step explanation:

7 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$