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postnew [5]
3 years ago
15

PROBLEM #1

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer:

  • 500 - 25w ≥ 200

Explanation:

Translate every verbal statement into an algebraic statement,

<u>1. Keith has $500 in a savings account at the beginning of the summer.</u>

  • Initial amount: 500

<u>2.  He wants to have at least $200 in the account by the end of summer. </u>

<u />

  • Final amount ≥ 200

<u>3. He withdraws $25 a week for his cell phone bill.</u>

<u />

  • Call w the number of weeks
  • Withdrawls = 25w

<u>4. Write an inequality that represents Keith's situation.</u>

  • Create your model: Final amount = Initial amount - withdrawals ≥ 500

  • 500 - 25w ≥ 200

With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:

  • 500 - 200 ≥ 25w
  • 300 ≥ 25w
  • 300/25 ≥ w
  • 12 ≥ w
  • w ≤ 12

That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.

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Step-by-step explanation:

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Answer is 3/72

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Use the number line below, where RS = 7y +5. ST = 3y +5, and RT = 70.<br> a. What is the value of y?
NeTakaya

Answer:

Step-by-step explanation:

7y+5+3y+5=70

10y+10=70

10y=60

y=6

7(6)+5= 42+5= 47

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3 years ago
A drawer contains 4 white socks, 5 black socks, and 3 brown socks. Find the probability that...
IRINA_888 [86]

Answer:

5/12

7/12

125/36 = 3,47%

50/11 = 4,54%

Step-by-step explanation:

Probability a black sock is selected when a person chooses 1 sock = 5/12

Probability a white or brown sock is selected when a person chooses 1 sock =

7/12

Probability  a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%

Pobability  a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%

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3 years ago
A practice law exam has 100 questions, each with 5 possible choices. A student took the exam and received 13 out of 100.If the s
Cloud [144]

Answer:

z=\frac{13-20}{4}=-1.75

Assuming:

H0: \mu \geq 20

H1: \mu

p_v = P(Z

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest (number of correct answers in the test), on this case we now that:

X \sim Binom(n=100, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=100*0.2=20 \geq 10

n(1-p)=20*(1-0.2)=16 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=100*0.2=20

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So we can approximate the random variable X like this:

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The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

The z score is given by this formula:

z=\frac{x-\mu}{\sigma}

If we replace we got:

z=\frac{13-20}{4}=-1.75

Let's assume that we conduct the following test:

H0: \mu \geq 20

H1: \mu

We want to check is the score for the student is significantly less than the expected value using random guessing.

So on this case since we have the statistic we can calculate the p value on this way:

p_v = P(Z

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