A positron, or an anti-electron, is a particle with a positive charge and the mass of an electron.
Australia separated from other continents and species there evolved independently
Answer:
It would become an ion and an isotope
Explanation:
If an atom loses an electron regardless of how many neutrons you add its an ion, It gained neutrons but it still has the same number of protons so it's an isotope.
The length of the rope Leo needs to purchase will be 45.3125 ft.
<h3 /><h3>How can you find out surface area ?</h3>
Surface area is calculated for common forms such as circles, triangles, parallelograms, rectangles, trapezoids, and so on.
When a form that isn't a standard figure appears, we slice it into standard shapes to get its area. The area of those component forms is then calculated and added together.
The surface area of the prism is,35 ft²
![\rm A_s=2\times A_b+P\times h \\\\ 35=2 \times 3 +BP \times 3.2\\\\\ 35=6+3.2 BP\\35-6=3.2BP\\\\ BP=\frac{29}{3.2} \\\\BP=9.0652\ ft](https://tex.z-dn.net/?f=%5Crm%20A_s%3D2%5Ctimes%20A_b%2BP%5Ctimes%20h%20%5C%5C%5C%5C%2035%3D2%20%5Ctimes%203%20%2BBP%20%5Ctimes%203.2%5C%5C%5C%5C%5C%2035%3D6%2B3.2%20BP%5C%5C35-6%3D3.2BP%5C%5C%5C%5C%20BP%3D%5Cfrac%7B29%7D%7B3.2%7D%20%5C%5C%5C%5CBP%3D9.0652%5C%20ft)
The length of the rope Leo needs to purchase;
L=5 ×9.0652
L=45.3125 ft
Hence,the length of the rope Leo needs to purchase will be 45.3125 ft.
To learn more about the area of a composite figure, refer:
brainly.com/question/10254615
#SPJ1
Answer:
Explanation:
Given
altitude of the Plane ![h=6\ miles](https://tex.z-dn.net/?f=h%3D6%5C%20miles)
When Airplane is
away
Distance is changing at the rate of ![\frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7D%20s%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D290%5C%20mph)
From diagram we can write as
![h^2+x^2=s^2](https://tex.z-dn.net/?f=h%5E2%2Bx%5E2%3Ds%5E2)
differentiate above equation w.r.t time
![2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}](https://tex.z-dn.net/?f=2h%5Cfrac%7B%5Cmathrm%7Bd%7D%20h%7D%7B%5Cmathrm%7Bd%7D%20t%7D%2B2x%5Cfrac%7B%5Cmathrm%7Bd%7D%20x%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D2s%5Cfrac%7B%5Cmathrm%7Bd%7D%20s%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
as altitude is not changing therefore ![\frac{\mathrm{d} h}{\mathrm{d} t}=0](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7D%20h%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D0)
![0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}](https://tex.z-dn.net/?f=0%2Bx%5Cfrac%7B%5Cmathrm%7Bd%7D%20x%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3Ds%5Cfrac%7B%5Cmathrm%7Bd%7D%20s%7D%7B%5Cmathrm%7Bd%7D%20t%7D)
at ![s=10\ miles\ and\ h=6\ miles](https://tex.z-dn.net/?f=s%3D10%5C%20miles%5C%20and%5C%20h%3D6%5C%20miles)
substitute the value we get ![x=\sqrt{10^2-6^2}=8\ miles](https://tex.z-dn.net/?f=x%3D%5Csqrt%7B10%5E2-6%5E2%7D%3D8%5C%20miles)
![8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290](https://tex.z-dn.net/?f=8%5Ctimes%20%5Cfrac%7B%5Cmathrm%7Bd%7D%20x%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D10%5Ctimes%20290)