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amm1812
3 years ago
11

PLEASE ANSWER THIS WILL MARK AS BRAINLIEST PLEASE USE TRUTHFUL ANSWERS PLEASE

Physics
1 answer:
luda_lava [24]3 years ago
8 0
Australia separated from other continents and species there evolved independently
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Which is a example of application of a scientific concept?
stira [4]
I think its c or d but im not quite sure.....
3 0
3 years ago
Does the depth of a pot affect how water freezes
Iteru [2.4K]
In my opinion it does. The more water the pot holds, the longer you need to wait for it to freeze. Since there is more water, some parts may not be completely frozen. An experiment you can try is to get an ice cube container and a pot. fill both of them and put them in the freezer for the same amount of time. When you take it out, the ice cubes should be frozen leaving the pot with cold water.
3 0
3 years ago
Read 2 more answers
The speed of an arrow fired from a compound
san4es73 [151]

Answer:

A.) The arrow`s range is 624,996 m

B.) The arrow`s range is 846.887 m, when the horse is galloping

Explanation:

We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.

By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.

<u>Equations</u>

X axis:

X=v_{ox}*t

v_{0x} =v_0cos(\alpha)

Y axis:

Y= Y_0 +v_{y0} t - \frac{g}{2} t^2

A.) First, it is necessary to know t, total time.

To figure out t value, we use UAM, since time is determined by this movement.

Now, at the end of the movement, Y=0, then

0= Y_0 +v_{y0} t - \frac{g}{2} t^2

0=2.4m+79m/s*sin(39)t-(1/2*9.81m/s^2)t^2

Caculate the segcond degree equation to obtain the two possible values for t:

t_1= 10.18 \\t_2= -0.04046

But, in physics, time it could not be negative, so we take t_1= 10.18

Caculate now:

X=79m/s*cos(\39)*10.18s= 624.996 m

B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.

v_0= 79m/s+13m/s= 92m/s

Using the same procedure that item A, caculate X

First, we need to know the new time

0=2.4m+92m/s*sin(39)t-(1/2*9.81m/s^2)t^2

And we obtain:

t_1=11.845s\\t_2=-0.041s

One more time, we take the positive time: t_1=11.845s

Finally:

X=92m/s *cos(39)*11.845s=846.887 m

6 0
3 years ago
What is the most likely place for a star to begin to form?
Rufina [12.5K]

Answer:

Stars are born within the clouds of dust and scattered throughout most galaxies. Deep within these clouds, turbulence creates knots with enough mass to cause the gas and dust to collapse under its own gravitational force.

4 0
3 years ago
A planetâs moon revolves around the planet with a period of 39 Earth days in an approximately circular orbit of radius of 4.8Ã10
Alchen [17]

Answer:

v = 895 m/s

Explanation:

Time period is given as 39 Earth Days

T = 39 days \times 24 hr \times 3600 s

T = 3369600 s

now the radius of the orbit is given as

r = 4.8 \times 10^8 m

so the total path length is given as

L = 2 \pi r

L = 2\pi (4.8 \times 10^8)

L = 3.015 \times 10^9

now the speed will be given as

v = \frac{L}{T}

v = \frac{3.015 \times 10^9}{3369600}

v = 895 m/s

7 0
3 years ago
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