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Ksju [112]
3 years ago
14

Which expression can be used to change 75 kilometers per hour to meters per minute?

Physics
2 answers:
son4ous [18]3 years ago
6 0
It helps you:
1\frac{km}{h}=1\cdot\frac{1000m}{3600s}=\frac{10}{36}\frac{m}{s}
75\frac{km}{h}=75\cdot\frac{1000m}{3600s}=\frac{750\cdot10}{36}\frac{m}{s}=\frac{750}{36}\frac{m}{s}~=20,83\frac{m}{s}
tiny-mole [99]3 years ago
5 0
When you say "Which...", does that mean you're looking at a list of choices
and not sharing it ?


To change (kilometers/hour) to (meters/minute), multiply (kilometers/hour) by

(1,000 meters/kilometer) x (hour/60 minutes).

Both of those fractions are equal to ' 1 ', so the process doesn't change the
original quantity, just its units. 
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dangina [55]

Answer:

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Explanation:

4 0
3 years ago
While skiing in Jackson, Wyoming, your
grin007 [14]
Hello!

Work is equal to negative change in PE and PE=mgh and Power is change in work/change in time

So we have 

56.1kg * 9.80m/s^2 * 16m = 8796.5 J of PE at top of run and -8796.5J of work done also

if it takes him 12s then we need to find the time gravity alone would bring him to the bottom. we get

16m=1/2at^2 and solving for t we get 
t=sqrt(32/9.80m/s^2)=1.81s

so the difference in time is 12-1.8=11.2s

now we can find avg power=work/time = 8796.5J/11.2s = 785W or 785J/s

Hope this helps! Any questions please ask! Thank you!
8 0
3 years ago
A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering
Black_prince [1.1K]
<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y is the height of the stone at 6s (the value we want to find)

y_{o}=925ft is the initial height of the stone

V_{o}=20ft/s is the initial velocity of the stone

t=6s is the time  at which we need to find the height

g=32ft/s^{2} is the acceleration due to gravity

Having this clear, let's find y from (1):

y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2} (2)

Finally:

y=469ft This is the height of the stone at t=6s

4 0
3 years ago
Please help me with question B.
Step2247 [10]
It accelerates in the y component (bc of gravity) AND the x-component (b/c of the friction force).
5 0
3 years ago
During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?
Mazyrski [523]

Answer:

C.) The slinky particles move up and down

Explanation:

<u>Transverse Wave</u>-

<em>A wave that has a disturbance perpendicular to the wave motion</em>

<em></em>

<em>Hello! This is the correct answer! Have a blessed day! :)</em>

<em>If you are in K12, please review the lesson! :)  It will give you some very helpful definitions!  I hope this helped!</em>

<u />

5 0
2 years ago
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