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Ksju [112]
3 years ago
14

Which expression can be used to change 75 kilometers per hour to meters per minute?

Physics
2 answers:
son4ous [18]3 years ago
6 0
It helps you:
1\frac{km}{h}=1\cdot\frac{1000m}{3600s}=\frac{10}{36}\frac{m}{s}
75\frac{km}{h}=75\cdot\frac{1000m}{3600s}=\frac{750\cdot10}{36}\frac{m}{s}=\frac{750}{36}\frac{m}{s}~=20,83\frac{m}{s}
tiny-mole [99]3 years ago
5 0
When you say "Which...", does that mean you're looking at a list of choices
and not sharing it ?


To change (kilometers/hour) to (meters/minute), multiply (kilometers/hour) by

(1,000 meters/kilometer) x (hour/60 minutes).

Both of those fractions are equal to ' 1 ', so the process doesn't change the
original quantity, just its units. 
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Answer:

i. -4m

ii. 20m

Explanation:

The car travels 8m to the east, then travels 12m to the west which is the opposite of the east. Going west, the car travels 8m back to the origin point and then another 4m due west to make 12m. The displacement from the origin point is -4 (the negative sign shows the direction because displacement is a vector quantity)

Total distance = 8m going east + 8m back to origin + 4m west = 20m

4 0
3 years ago
Cognitive psychology deals with ____.
Elanso [62]

Answer:

B

Explanation:

Because the main focus of cognitive psychology is on the metal processes that affect behavior

3 0
2 years ago
An object accelerates 3.0 m/s2 when a force of 6.0 N is applied to it. What is the mass of the object?
makvit [3.9K]

Answer:

<h2>2 kg</h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

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m =  \frac{6}{3}  \\

We have the final answer as

<h3>2 kg</h3>

Hope this helps you

5 0
3 years ago
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4 years ago
A mass moves back and forth in simple harmonic motion with amplitude A and period T.
Sever21 [200]

a. 0.5 T

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- The period T is the time the system takes to complete one oscillation

During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

1 T : 4 A = t : 2 A

and solving for t we find

t=\frac{(1T)(2 A)}{4A}=0.5 T

b. 1.25T

Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that

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we can set the following proportion:

1 T : 4 A = t : 5 A

And by solving for t, we find

t=\frac{(1T)(5 A)}{4A}=\frac{5}{4} T=1.25 T

6 0
3 years ago
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