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Ksju [112]
2 years ago
14

Which expression can be used to change 75 kilometers per hour to meters per minute?

Physics
2 answers:
son4ous [18]2 years ago
6 0
It helps you:
1\frac{km}{h}=1\cdot\frac{1000m}{3600s}=\frac{10}{36}\frac{m}{s}
75\frac{km}{h}=75\cdot\frac{1000m}{3600s}=\frac{750\cdot10}{36}\frac{m}{s}=\frac{750}{36}\frac{m}{s}~=20,83\frac{m}{s}
tiny-mole [99]2 years ago
5 0
When you say "Which...", does that mean you're looking at a list of choices
and not sharing it ?


To change (kilometers/hour) to (meters/minute), multiply (kilometers/hour) by

(1,000 meters/kilometer) x (hour/60 minutes).

Both of those fractions are equal to ' 1 ', so the process doesn't change the
original quantity, just its units. 
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An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux
zhenek [66]

Answer:

\phi=1.56\times 10^{-5}\ Wb

Explanation:

Given that,

Emf, V = 22 mV

Number of turns in the coil us 519

Rate of change of current is 10 A/s.

We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.

Let's find the inductance first. So,

L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H

We have,

L=\dfrac{N\phi}{I}, \phi is magnetic flux

\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb

So, the magnetic flux is 1.56\times 10^{-5}\ Wb.

8 0
2 years ago
A cat’s crinkle ball toy of mass 15g is thrown straight up with an initial speed of 3m/s. Assume in this problem that air drag i
stiks02 [169]

Answer:

P.E = 0.068 J = 68 mJ

Explanation:

First we need to find the height attained by the ball toy. For this purpose, we will be using 3rd equation of motion:

2gh = Vf² - Vi²

where,

g = -9.8 m/s²  (negative sign due to upward motion)

h = height attained by the ball toy = ?

Vf = Final Velocity = 0 m/s (since it momentarily stops at the highest point)

Vi = Initial Velocity = 3 m/s

Therefore,

2(-9.8 m/s²)h = (0 m/s)² - (3 m/s)²

h = (9 m²/s²)/(19.6 m/s²)

h = 0.46 m

Now, the gravitational potential energy of ball at its peak is given by the following formula:

P.E = mgh

P.E = (0.015 kg)(9.8 m/s²)(0.46 m)

<u>P.E = 0.068 J = 68 mJ</u>

4 0
3 years ago
Genevieve was working on a science lab. In her lab, she was combining two chemicals and timing how long the reaction took to for
dexar [7]

Answer: Her test trials had a high level of accuracy but a low level of precision.

Explanation:

5 0
3 years ago
A bedroom bureau with a mass of 45 kg, including drawers and clothing, rests on the floor. (a) If the coefficient of static fric
sergij07 [2.7K]

Answer: the minimal force that you need to apply to move the bureau is F = 198.45N

Explanation:

If you want to move an object, you need to apply a force that is bigger than the force of the statical friction.

The force of statical friction can be written as.

Ff = k*N

where k is the coefficient of static friction, in this case, k = 0.45, and N is the normal force between the object and the surface.

In this case, the normal force is the weight of the bedroom bureau, this is:

N = m*g = 45kg*9.8m/s^2 = 441N

Then the force is:

Fr = 0.45*441N = 198.45N

This means that the minimal force that you need to apply to move the bureau is F = 198.45N

and after this point, the force of friction will work wit the kinetic coefficient of friction, that usually is smaller than the statical one.

4 0
3 years ago
which of the following is not necessary in a great summary?your investigayltion, your predicatio, excuses, possible errors?
zloy xaker [14]

Excuse are not acceptable


5 0
3 years ago
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