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Ksju [112]
3 years ago
14

Which expression can be used to change 75 kilometers per hour to meters per minute?

Physics
2 answers:
son4ous [18]3 years ago
6 0
It helps you:
1\frac{km}{h}=1\cdot\frac{1000m}{3600s}=\frac{10}{36}\frac{m}{s}
75\frac{km}{h}=75\cdot\frac{1000m}{3600s}=\frac{750\cdot10}{36}\frac{m}{s}=\frac{750}{36}\frac{m}{s}~=20,83\frac{m}{s}
tiny-mole [99]3 years ago
5 0
When you say "Which...", does that mean you're looking at a list of choices
and not sharing it ?


To change (kilometers/hour) to (meters/minute), multiply (kilometers/hour) by

(1,000 meters/kilometer) x (hour/60 minutes).

Both of those fractions are equal to ' 1 ', so the process doesn't change the
original quantity, just its units. 
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What are the units for the spring constant, k? A. newton meters B. newton seconds C. newtons/meter D. newtons/second E. newtons/
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Answer:

C. N/m (newtons/meter)

Explanation:

Since the equation for potential energy for a spring is PE = 1/2kx², after you know <em>k </em>and <em>x</em>, you will get an answer in Joules.

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3 years ago
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12. An object accelerates 16.3 m/s2 when a force of 4.6 newtons is applied to it.
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The acceleration of body is given 16.3m/s2 and the force is given 4.6 N then
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A solenoid 1.85 m long and 2.20 cm in diameter carries a current of 21.0 A. The magnetic field inside the solenoid is 25.0 mT. F
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A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 2.16-N force on the 4.00 cm of wire in the field. What is the average field strength?

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2 years ago
Name any two liquid which are found in our human eyes​
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8 0
3 years ago
Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr
Illusion [34]

Answer:

F_{sprinter}=110.4N

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

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W=F_{total}.d

So

W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N  

7 0
3 years ago
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